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Trigonometric Functions: Radians, Unit Circle, Graphs and Identities

An angle of one radian cuts an arc equal to the radius, so π radians = 180°. On a unit circle, the point at angle x is P = (cos x, sin x), which gives sin²x + cos²x = 1 and extends sine and cosine to every real number. The signs follow 'All, Sin, Tan, Cos' in quadrants I to IV; sin x and cos x repeat every 2π and stay between −1 and 1. Compound-angle formulas such as cos(A + B) = cos A cos B − sin A sin B lead to tan(A + B), cot(A + B), sum-to-product, double-angle and triple-angle identities.

🎬 Step-by-step story

  1. A circle of radius 2. A green arc grows until it is exactly as long as the radius. The angle at the centre is 1 radian, about 57.3°.
  2. Now call the radius 1 unit: a unit circle. Point P at angle x. Its across distance (blue) is cos x, its up distance (red) is sin x. The slanted side is 1, so sin²x + cos²x = 1.
  3. Move P to 150°. It is in quadrant II: across is negative, up is positive. So sin is +, cos is −. Labels show the sign rule for all four quadrants.
  4. P goes round and round. Its height is copied to the right, one degree at a time, and draws the wave y = sin x. After 360° the wave repeats.
  5. Angle A (green) then angle B (purple) added on top. P lands at A + B. The readout checks cos A cos B − sin A sin B = cos(A + B).
  6. Free play: slide the angle x and watch cos x, sin x, tan x and the identity.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why do we need radians when degrees work?

Radians measure angle by arc length (l = rθ), so they make formulas and calculus simple. Step 1 shows the arc equal to the radius.

How can sin 200° exist if there is no right triangle with a 200° angle?

On the unit circle sin x is just the height of P. P can be at any angle, even 200°, so sin works for all x.

How do I remember which ratios are positive?

All Students Take Coffee: All in I, Sin in II, Tan in III, Cos in IV. Step 3 shows the labels.

Why does sin x never go above 1?

sin x is the height of a point on a circle of radius 1. It cannot be higher than the top of the circle.

Why is sin(A + B) not sin A + sin B?

Try A = B = 30°: sin 60° ≈ 0.866 but sin 30° + sin 30° = 1. In step 5 the readout shows the real formula works.

Where does tan x become undefined?

tan x = sin x/cos x, so at 90°, 270°, … where cos x = 0. Slide to 90° in free play: the readout drops tan.

Degrees and radians

One radian is the angle at the centre when the arc is as long as the radius (step 1 of the 3D). The whole circle has arc 2πr, so it is 2π radians.

Unit-circle definitions and sin²x + cos²x = 1

Draw a circle of radius 1 with centre at the origin. Turn a radius by angle x from the positive x-axis. It ends at P(a, b). We define cos x = a and sin x = b.

This works for every real x, even more than 360° or negative. Then tan x = sin x / cos x (cos x ≠ 0), cot x = cos x / sin x, sec x = 1/cos x, cosec x = 1/sin x.

P is at distance 1 from the centre, so by Pythagoras a² + b² = 1, which is sin²x + cos²x = 1. Divide by cos²x: 1 + tan²x = sec²x. Divide by sin²x: 1 + cot²x = cosec²x.

Signs, domain, range and graphs

Quadrant signs (step 3): I all +, II sin and cosec +, III tan and cot +, IV cos and sec +.

Step 4 draws y = sin x from the circle: it starts at 0, peaks at 1 at π/2, returns to 0 at π, drops to −1 at 3π/2. cos x is the same wave shifted left by π/2.

Sum and difference formulas

Special cases: cos(π/2 − x) = sin x, sin(π/2 − x) = cos x, sin(π − x) = sin x, cos(π − x) = −cos x, sin(π + x) = −sin x, cos(2π − x) = cos x.

Idea of the proof (in our own steps): put P at angle A + B and Q at angle 0; then put R at angle A and S at angle −B. The chord PQ and the chord RS subtend the same angle A + B, so they are equal. Write both with the distance formula, simplify using sin² + cos² = 1, and cos(A + B) comes out. The rest follow by replacing B with −B or A with π/2 − A.

Double, triple angle and sum-to-product

Double angle (put B = A)

Triple angle

Sum to product

And back: 2 sin x cos y = sin(x + y) + sin(x − y), 2 cos x cos y = cos(x + y) + cos(x − y), −2 sin x sin y = cos(x + y) − cos(x − y).

Try it

At home: tie a thread to a bottle cap, stretch it as a radius, then lay the same length of thread along the rim of a round plate. Mark the angle it makes at the centre: that is 1 radian. How many such threads fit round the rim? (A little more than 6, because 2π ≈ 6.28.)

In the 3D: in step 5 set A = 45°, B = 30° and check the readout gives sin 75° ≈ 0.966. In free play, predict the sign of cos 200° before you slide.

Key formulas and definitions

Worked examples

1. Convert 40°20′ into radians.

40°20′ = 40⅓° = 121/3°. Radians = (121/3) × π/180 = 121π/540.

2. Convert 6 radians into degrees (π ≈ 22/7).

6 × 180/π = 1080 × 7/22 ≈ 343.64° ≈ 343°38′.

3. A wheel of radius 35 cm turns through 72°. How far does a point on the rim move?

θ = 72 × π/180 = 2π/5. l = rθ = 35 × 2π/5 = 14π ≈ 44 cm.

4. If cos x = −3/5 and x is in quadrant III, find the other five ratios.

sin²x = 1 − 9/25 = 16/25. In III sin is negative: sin x = −4/5. tan x = (−4/5)/(−3/5) = 4/3, cot x = 3/4, sec x = −5/3, cosec x = −5/4.

5. Find sin 765° and cos(−1710°).

765° = 2 × 360° + 45°, so sin 765° = sin 45° = 1/√2. −1710° = −5 × 360° + 90°, so cos(−1710°) = cos 90° = 0.

6. Find sin 75° (the worked example in step 5).

sin(45° + 30°) = sin 45° cos 30° + cos 45° sin 30° = (1/√2)(√3/2) + (1/√2)(1/2) = (√3 + 1)/(2√2) ≈ 0.966.

7. Find tan 15°.

tan(45° − 30°) = (1 − 1/√3)/(1 + 1/√3) = (√3 − 1)/(√3 + 1) = (√3 − 1)²/2 = (4 − 2√3)/2 = 2 − √3.

8. Prove (sin 5x + sin 3x)/(cos 5x + cos 3x) = tan 4x.

Numerator = 2 sin 4x cos x; denominator = 2 cos 4x cos x (sum to product). Ratio = sin 4x / cos 4x = tan 4x.

9. If sin x = 1/3, find sin 3x and cos 2x.

sin 3x = 3(1/3) − 4(1/27) = 1 − 4/27 = 23/27. cos 2x = 1 − 2(1/9) = 7/9.

Common mistakes

Practice quiz

1. π/3 radians in degrees is:
2. In which quadrant are both sin and cos negative?
3. Range of cos x is:
4. cos(A − B) equals:
5. cos 2x is NOT equal to:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

How do you convert degrees to radians?

Multiply the degrees by π/180. For example, 60° = 60π/180 = π/3.

What is the formula of cos(A + B)?

cos(A + B) = cos A cos B − sin A sin B.

What are the triple angle formulas?

sin 3x = 3 sin x − 4 sin³x, cos 3x = 4 cos³x − 3 cos x, tan 3x = (3 tan x − tan³x)/(1 − 3 tan²x).

Where this is taught

Canada (Ontario)Grade 11C. Trigonometric Functions
Canada (Ontario)Grade 11D. Trigonometric Functions
Canada (Ontario)Grade 12C. Trigonometric Functions
Canada (Ontario)Grade 12B. Trigonometric Functions
ItalySecondaria di secondo grado – classe 3ªGeometry
ItalySecondaria di secondo grado – classe 3ªGeometry
ItalySecondaria di secondo grado – classe 4ªGeometry
ItalySecondaria di secondo grado – classe 4ªGeometry
NetherlandsHAVO 5 (eindexamenjaar)Functions, graphs and equations (part 2)
NetherlandsVWO 5Trigonometric functions
PolandLiceum ogólnokształcące, klasa IITrigonometry
RomaniaClasa a IX-aTrigonometry: Trigonometric functions and equations
RomaniaClasa a IX-aTrigonometry and applications in geometry
RomaniaClasa a IX-aTrigonometry: Elements of trigonometry
Ukraine10 класAlgebra: trigonometric functions (42 h)
Ukraine10 класAlgebra: trigonometric functions (34 h)
Ukraine10 класAlgebra: trigonometric functions (18 h)
CBSE (India)Class 11Sets and Functions
England (GCSE, A level)Year 12E Trigonometry
England (GCSE, A level)Year 13E Trigonometry
USA (Common Core, NGSS, AP)Grade 11Trigonometric functions
USA (Common Core, NGSS, AP)Grade 11Trigonometry of general triangles and trigonometric functions
USA (Common Core, NGSS, AP)Grade 12Polynomial and Rational Functions
USA (Common Core, NGSS, AP)Grade 12Trigonometric and Polar Functions
USA (Common Core, NGSS, AP)Grade 12Trigonometry
Japan高校(専門学科)1〜3年Advanced Mathematics II
Japan高校2年Trigonometric functions
South Korea고등학교 2학년Trigonometric functions
South Korea고등학교 2학년Differentiation techniques
South Korea고등학교 3학년Trigonometric functions
Germany (Bavaria)Jahrgangsstufe 10Sine and cosine functions
FrancePremièreAnalysis
FrancePremièreMathematics
FrancePremièreMathematics
FranceTerminaleAnalysis
Russia10 классNumbers and calculations
Russia10 классNumbers and calculations
Russia10 классEquations and inequalities
Russia10 классFunctions and graphs
Russia11 классFunctions and graphs
China高一Ch.5 Trigonometric functions

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