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Reflection of Light: Plane and Spherical Mirrors

Light bounces off a shiny surface so that the angle of incidence equals the angle of reflection. A plane mirror gives a virtual, upright, same-size image as far behind as the object is in front. A concave mirror can give real or virtual images depending on where the object is; a convex mirror always gives a virtual, upright, smaller image. The mirror formula 1/v + 1/u = 1/f and magnification m = −v/u (with the New Cartesian sign convention) let you find the image without drawing.

🎬 Step-by-step story

  1. A ray hits a flat mirror at the pole P. Here the axis is the normal. The ray leaves at the same angle it came in: angle i equals angle r.
  2. A plane mirror makes the image behind the glass: upright, the same size, and as far behind as the object is in front. The rays only seem to come from there, so the image is virtual (dotted lines).
  3. Now a concave mirror, curved inward like a spoon. Rays parallel to the axis all bounce through one point, the focus F. The centre of curvature C is twice as far away: R = 2f.
  4. Watch the object walk toward the concave mirror: beyond C, at C, between C and F, at F, then inside F. The image grows, runs away to infinity, and finally jumps behind the mirror, upright.
  5. A convex mirror bulges outward. Parallel rays spread out as if they came from F behind it. Wherever you put the object, the image is behind the mirror: virtual, upright and smaller.
  6. Your turn. Drag the green object, change f, or pick another mirror. The readout solves 1/v + 1/u = 1/f and m = −v/u with the correct signs.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why is the angle measured from the normal and not the mirror?

The normal is the same for every direction around the point, so it gives one clear reference. In step 1 the axis is the normal at P and the two angles on either side are equal.

Why can't a plane-mirror image be caught on a screen?

The reflected rays go back toward you and never meet behind the mirror. Only their dotted backward extensions meet, which makes the image virtual. See step 2.

Why is F exactly halfway between P and C?

Each parallel ray bounces symmetrically about the normal (which points to C). For rays near the axis, this sends them through the midpoint of PC, so f = R/2. Step 3 shows all parallel rays crossing at F.

What happens when the object is exactly at F?

The reflected rays come out parallel and never meet, so the image is 'at infinity'. In step 4 the image vanishes at that moment; move the object a little either side to see it come back.

Can a convex mirror ever make a real or bigger image?

No. Its reflected rays always spread out, so they only seem to meet behind the mirror between P and F: always virtual, erect and smaller. Drag the object in step 5 to check.

How do I know the sign of the answer is right?

Use the free-play bench: the readout shows u, v, f and m with signs and the drawn image matches them. Negative v means the image is in front (real); positive v means behind (virtual).

What is reflection? The two laws of reflection

When light falls on a smooth shiny surface and bounces back into the same medium, we call it reflection. The ray that arrives is the incident ray, the ray that leaves is the reflected ray, and the line drawn at 90° to the surface at the point where the ray hits is the normal.

  1. First law: the angle of incidence equals the angle of reflection (∠i = ∠r). Both angles are measured from the normal, not from the mirror.
  2. Second law: the incident ray, the normal at that point and the reflected ray all lie in the same plane.

These laws hold for every reflecting surface: flat mirrors, curved mirrors, even water. For a curved mirror the normal at a point is the line joining that point to the centre of curvature.

Image formed by a plane mirror

A plane (flat) mirror always gives an image that is:

Spherical mirrors: concave and convex

A spherical mirror is a piece cut from a hollow shiny sphere. If the shiny side is the inner (caved-in) side, it is a concave mirror; if the shiny side bulges out, it is a convex mirror.

Important terms

For mirrors with a small aperture, R = 2f, so F lies halfway between P and C.

Rules for drawing ray diagrams

To locate an image, take any two of these rays from the tip of the object. Where they meet (or seem to meet) is the tip of the image.

  1. A ray parallel to the principal axis passes through F after reflection (concave) or seems to come from F (convex).
  2. A ray passing through F (concave) or heading toward F (convex) comes back parallel to the axis.
  3. A ray through C (concave) or heading toward C (convex) hits the mirror along the normal and comes straight back on itself.
  4. A ray hitting the pole bounces back at the same angle on the other side of the axis (the axis is the normal at P).

In the 3D bench the orange ray uses rule 1 and the teal ray uses rule 4. Dotted lines show where reflected rays only seem to come from: that is a virtual image.

Image formation by a concave mirror (every object position)

Object positionImage positionSizeNature
At infinityAt FPoint-sized, highly diminishedReal, inverted
Beyond CBetween F and CDiminishedReal, inverted
At CAt CSame sizeReal, inverted
Between C and FBeyond CEnlargedReal, inverted
At FAt infinityHighly enlargedReal, inverted
Between P and FBehind the mirrorEnlargedVirtual, erect

Pattern to notice: as the object comes closer from infinity to F, the real image moves away from F toward infinity and keeps growing. Inside F the image becomes virtual and upright. Walk through all six cases in story step 4 or by dragging the object.

Image formation by a convex mirror

Object positionImage positionSizeNature
At infinityAt F, behind the mirrorPoint-sizedVirtual, erect
Anywhere between infinity and PBetween P and F, behind the mirrorDiminishedVirtual, erect

The image of a convex mirror never crosses F and is never real. The closer the object, the bigger (but still smaller than the object) the image.

Uses of concave and convex mirrors

New Cartesian sign convention for spherical mirrors

Results: a concave mirror has negative f; a convex mirror has positive f. A real image (in front) has negative v; a virtual image (behind) has positive v.

Mirror formula and magnification

The object distance u, image distance v and focal length f are linked by the mirror formula:

1/v + 1/u = 1/f

Magnification tells how many times bigger the image is and whether it is upright:

m = h′/h = −v/u

How to solve: write the known values with signs, put them into the formula, solve for the unknown, then read the sign of the answer to decide the nature. Board papers usually ask one ray diagram (2–3 marks) and one numerical on the mirror formula (3 marks) from this part.

Key formulas and definitions

Worked examples

1. A concave mirror has a radius of curvature of 30 cm. What is its focal length (with sign)?

f = R/2 = 30/2 = 15 cm. F is in front of a concave mirror, against the incident light, so f = −15 cm.

2. A convex mirror has a focal length of 12 cm. Find its radius of curvature.

R = 2f = 2 × 12 = 24 cm. The centre of curvature is behind the mirror, so R = +24 cm.

3. An object is placed 30 cm in front of a concave mirror of focal length 20 cm. Find the image position, magnification and nature.

u = −30 cm, f = −20 cm. 1/v = 1/f − 1/u = −1/20 + 1/30 = (−3 + 2)/60 = −1/60, so v = −60 cm. m = −v/u = −(−60)/(−30) = −2. The image is 60 cm in front of the mirror: real, inverted, twice as big (object between C and F, image beyond C).

4. An object 4 cm tall stands 10 cm in front of a concave mirror of focal length 15 cm. Find the image position and height.

u = −10, f = −15. 1/v = −1/15 + 1/10 = (−2 + 3)/30 = 1/30, so v = +30 cm (behind the mirror). m = −v/u = −30/(−10) = +3. h′ = m × h = 3 × 4 = 12 cm. Virtual, erect, 3 times enlarged: this is how a shaving mirror works.

5. An object is 20 cm in front of a convex mirror of focal length 20 cm. Find the image.

u = −20, f = +20. 1/v = 1/20 − 1/(−20) = 1/20 + 1/20 = 1/10, so v = +10 cm. m = −10/(−20) = +0.5. Image 10 cm behind the mirror, virtual, erect, half the size.

6. A concave mirror forms a real image, three times the size of the object, on a screen 60 cm from the mirror. Where is the object and what is the focal length?

Real image on a screen: v = −60 cm and m = −3 (real images are inverted). m = −v/u → −3 = 60/u → u = −20 cm. 1/f = 1/v + 1/u = −1/60 − 1/20 = (−1 − 3)/60 = −4/60, so f = −15 cm. Object 20 cm in front; focal length 15 cm.

7. A car's convex rear-view mirror has R = 3 m. A bus is 5 m behind it. Find the position and size ratio of the bus's image.

f = R/2 = +1.5 m, u = −5 m. 1/v = 1/1.5 + 1/5 = 0.667 + 0.200 = 0.867, so v ≈ +1.15 m. m = −v/u = 1.15/5 ≈ 0.23. The image is 1.15 m behind the mirror, virtual, erect and about a quarter of the size, so a large area fits in a small mirror.

Common mistakes

Practice quiz

1. The angle of reflection is measured from:
2. The focal length of a concave mirror of radius 40 cm is:
3. Which mirror always forms a virtual, erect and diminished image?
4. For a concave mirror, where must the object be to get an image of the same size?
5. A magnification of −2 means the image is:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is the mirror formula for Class 10?

1/v + 1/u = 1/f, where u is the object distance, v the image distance and f the focal length, all measured from the pole with the New Cartesian sign convention.

What is the difference between a concave and a convex mirror?

A concave mirror curves inward and can form real or virtual images depending on the object position. A convex mirror curves outward and always forms a virtual, erect, diminished image.

Why is magnification negative for a real image?

A real image is inverted, so its height has the opposite sign to the object's height. Since m = h′/h, m comes out negative.

Where this is taught

Canada (Ontario)Grade 10E. Physics: Light and Geometric Optics
Canada (Ontario)Grade 10E. Physics: Light and Applications of Optics
ItalySecondaria di secondo grado – classe 1ªFoundations, optics, heat and mechanics
ItalySecondaria di secondo grado – classe 2ªFoundations, optics, heat and mechanics
PolandSzkoła podstawowa, klasa VIIIOptics
RomaniaClasa a VIII-aOptical phenomena
Spain2º BachilleratoVibrations and waves
Ukraine9 класLight phenomena
CBSE (India)Class 10Natural Phenomena
Russia9 классLight phenomena
Russia9 классLight phenomena
China八年级(初二)Ch.4 Light

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