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The Unit Circle: Symmetry and Periodicity

The unit circle has radius 1 and centre at the origin. A point at angle θ has coordinates (cos θ, sin θ). Mirror images of this point give the rules for π − θ, π + θ and −θ, and going once round (2π) brings you back, so sine and cosine repeat every 2π and tangent every π.

🎬 Step-by-step story

  1. Here is a circle of radius 1 with its centre at the origin. Point P sits at angle θ = 30°. Its x-coordinate is cos θ and its y-coordinate is sin θ.
  2. Now mirror P in the y-axis. The new point Q is at 180° − θ. Its x changes sign, its y stays the same. So sin(180° − θ) = sin θ.
  3. Turn P half a circle. Q is at 180° + θ, exactly opposite P. Both x and y change sign. So tan(180° + θ) = tan θ.
  4. Mirror P in the x-axis. Q is at −θ. Only y changes sign. So cos(−θ) = cos θ (even) and sin(−θ) = −sin θ (odd).
  5. Watch P go one full turn of 360° (2π). It lands on the same spot, so every trig value repeats. The period of sin and cos is 2π.
  6. Your turn: move the angle slider from −360° to 720° and watch P and its mirror point. Predict the signs before you look.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why is cos the x-coordinate and not the y?

For an acute angle, the side next to the angle lies along the x-axis and the hypotenuse is 1, so adjacent ÷ hypotenuse = x.

How can sin 150° equal sin 30° when the angles are different?

The two points are mirror images in the y-axis, so they are at the same height y.

Why is tan the same for θ and 180° + θ?

The opposite point has both coordinates negative, and a negative divided by a negative gives the same positive ratio.

What does "cos is even" actually mean?

Turning clockwise by θ or anticlockwise by θ lands at the same x, so cos(−θ) = cos θ.

Can an angle be more than 360°?

Yes. You just keep turning; after each full turn the point repeats, so sin 390° = sin 30°.

What is the unit circle?

The unit circle is a circle with radius 1 and centre (0, 0). We measure an angle θ from the positive x-axis, turning anticlockwise. Where the arm of the angle meets the circle we get a point P.

We define: cos θ = x-coordinate of P, sin θ = y-coordinate of P, tan θ = y ÷ x. Because the radius is 1, these agree with SOH CAH TOA for acute angles, but now they work for any angle, even 200° or −45°.

Every point on the circle obeys x² + y² = 1, so sin²θ + cos²θ = 1.

Exact values: 30°, 45°, 60° and the quadrants

Half of a square (45°-45°-90°) and half of an equilateral triangle (30°-60°-90°) give exact values:

Radians: one full turn = 2π, so 180° = π. Multiply degrees by π/180 to change to radians.

Signs: in quadrant I all are +; in II only sin is +; in III only tan is +; in IV only cos is +.

Symmetry: mirror angles

The circle is symmetric, so mirror points give new values for free:

The reference angle is the acute angle between the arm and the x-axis. Find the value for the reference angle, then fix the sign using the quadrant.

Because cos(−θ) = cos θ, cosine is an even function (its graph is symmetric about the y-axis). Because sin(−θ) = −sin θ, sine is odd (its graph is symmetric about the origin). Tangent is odd too.

Periodicity

Adding 2π brings P back to the same point. So sin(θ + 2π) = sin θ and cos(θ + 2π) = cos θ. The smallest such shift is the period: 2π for sin and cos.

For tan, half a turn already works: P and the opposite point give the same y ÷ x, so the period of tan is π.

Use it to simplify big angles: 750° = 2 × 360° + 30°, so sin 750° = sin 30° = 1/2.

Try it

In the 3D, set θ = 45°, then 135°, 225° and 315°. Write down (x, y) each time. You will see the same number √2/2 ≈ 0.71 with different signs. At home: draw a circle of radius 10 cm on graph paper, mark 30° with a protractor and measure x and y. Divide by 10: you get about 0.87 and 0.5.

Key formulas and definitions

Worked examples

1. Find the coordinates of P on the unit circle at θ = π/3.

π/3 = 60°. From the 30-60-90 triangle, cos 60° = 1/2 and sin 60° = √3/2. So P = (1/2, √3/2).

2. Find sin 150°.

150° = 180° − 30° (quadrant II). Reference angle 30°. sin is positive in II. sin 150° = sin 30° = 1/2.

3. Find cos 225°.

225° = 180° + 45° (quadrant III). cos is negative in III. cos 225° = −cos 45° = −√2/2.

4. Find tan(−π/4).

tan is odd: tan(−π/4) = −tan(π/4) = −1.

5. Find sin(11π/6).

11π/6 = 2π − π/6 (quadrant IV). sin is negative in IV. sin(11π/6) = −sin(π/6) = −1/2.

6. Simplify cos 780° and tan 600°.

780° − 2 × 360° = 60°, so cos 780° = cos 60° = 1/2. tan has period 180°: 600° − 3 × 180° = 60°, so tan 600° = tan 60° = √3.

7. If sin θ = 3/5 and θ is in quadrant II, find cos θ and tan θ.

cos²θ = 1 − 9/25 = 16/25, so cos θ = ±4/5. In II cos is negative: cos θ = −4/5. tan θ = (3/5) ÷ (−4/5) = −3/4.

Common mistakes

Practice quiz

1. On the unit circle, cos θ is the…
2. sin(π − θ) equals
3. Which function is even?
4. The period of tan θ is
5. cos 300° equals

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is the unit circle used for?

It defines sin, cos and tan for every angle, gives exact values and explains their symmetry and repeating graphs.

How do I remember unit circle values?

Learn 30°, 45°, 60° from the two special triangles, then use reference angles and the ASTC sign rule for the rest.

What is a reference angle?

The acute angle between the terminal arm and the x-axis. The trig values of any angle equal ± the values of its reference angle.

Where this is taught

USA (Common Core, NGSS, AP)Grade 12Trigonometry

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