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Exponential, Logarithmic and Irrational Inequalities

Three families of inequalities share one idea: compare two graphs. For powers and logs the base decides whether the sign flips (base above 1 keeps it, base between 0 and 1 flips it). For logs and roots the domain must be checked first, and a root inequality needs care about the sign of the other side.

🎬 Step-by-step story

  1. We compare two graphs. The blue curve is 2ˣ and the orange line is 4. The green bar shows every x where blue is above orange.
  2. Now the base is 1/2. The curve falls instead of rising, so the green bar moves to the left side. The sign flips.
  3. A logarithm lives only for x above 0. The red bar is the forbidden zone. The green bar stops at x = 8.
  4. A square root lives only from x = −2. Blue is above orange from −2 up to 2. Domain first, then compare.
  5. Flip the question: root below the line. Now only x above 2 works. Slide the test x to x = 0 and see it fail.
  6. Free play. Pick any inequality, slide the test x, and check that TRUE appears only inside the green bar.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why does the sign flip when the base is 1/2?

A base between 0 and 1 makes the power smaller as the exponent grows. So a bigger power needs a smaller exponent.

Why is x = 0 or a negative number not allowed in log x?

No power of a positive base can give 0 or a negative number. So the curve does not exist there.

Why must I check the domain of a root first?

The root only exists from x = −2 in this example. The green bar cannot start before that.

Why can I not just square both sides?

If the right side is negative, squaring turns it positive and changes the meaning. Test x = 0 in the root below line case: it fails.

How can I be sure my answer is right?

Test one number inside and one outside. TRUE only inside the green bar means you are right.

Exponential inequalities: look at the base

An exponential inequality has the unknown in the power, like 2ˣ > 8. (A power is the small raised number.)

Step 1: write both sides with the same base: 2ˣ > 2³.

Step 2: compare the powers. The base decides:

A power is never zero or negative, so something like 2ˣ > −5 is true for every x, and 2ˣ < −5 is never true.

Hidden quadratic: for 4ˣ − 3·2ˣ + 2 < 0, put t = 2ˣ (t > 0). Then t² − 3t + 2 < 0, so 1 < t < 2, so 0 < x < 1.

Logarithmic inequalities: domain first

A logarithm answers "which power gives this number?". log₂ 8 = 3 because 2³ = 8. It only exists when the number inside is greater than 0.

To solve loga f(x) < loga g(x):

  1. Write the domain: f(x) > 0 and g(x) > 0.
  2. Base above 1: keep the sign, f < g. Base between 0 and 1: flip it, f > g.
  3. Join the answer with the domain (take only the part that is in both).

Example: log₂(x − 1) < 3. Domain: x > 1. Compare: x − 1 < 8, so x < 9. Answer: 1 < x < 9.

Turn a plain number into a log when needed: 3 = log₂ 8.

Irrational (root) inequalities

An irrational inequality has the unknown under a root, like √(x + 2) < x. A square root is never negative, and the thing under it cannot be negative.

Case √f < g (root is small). All three must hold together: f ≥ 0, g > 0, and f < g².

Case √f > g (root is big). Two roads, then join them with "or":

Never square both sides unless you know both sides are not negative. Squaring is only safe then.

Example: √(x + 2) < x. Domain x ≥ −2. Need x > 0. Square: x + 2 < x², so x² − x − 2 > 0, so x > 2 or x < −1. With x > 0 the answer is x > 2.

Check every answer

Pick one number inside your answer and one outside. Put both in the original inequality. Inside must say TRUE, outside must say FALSE (or "not allowed"). In the 3D board the green bar is the true zone and the red bar is the forbidden zone.

For mixed problems use a sign chart: mark the points where each part changes, test a number in every gap, and keep the gaps that are true.

Try it: predict, then check

In the 3D board pick 2^x > 4. Before you slide, guess: is x = 1 in the green bar? Slide the test x to 1 and read TRUE or FALSE. Now pick (1/2)^x > 4 and guess again for x = 1. At home: fold a paper in half again and again. After 5 folds there are 2⁵ = 32 layers. How many folds give more than 1000 layers? (2ˣ > 1000 gives 10 folds.)

Key formulas and definitions

Worked examples

1. Solve 3ˣ > 27.

27 = 3³, so 3ˣ > 3³. Base 3 is above 1, so keep the sign: x > 3.

2. Solve (1/2)^(x − 1) ≥ 1/8.

1/8 = (1/2)³. So (1/2)^(x − 1) ≥ (1/2)³. Base is between 0 and 1, so flip: x − 1 ≤ 3, so x ≤ 4.

3. Solve log₂(x − 1) < 3.

Domain: x − 1 > 0, so x > 1. Since 3 = log₂ 8, we need x − 1 < 8, so x < 9. Answer: 1 < x < 9.

4. Solve log_{1/3}(2x − 1) > −1.

Domain: 2x − 1 > 0, so x > 1/2. Write −1 = log_{1/3} 3. Base is below 1, so flip: 2x − 1 < 3, so x < 2. Answer: 1/2 < x < 2.

5. Solve 4ˣ − 3·2ˣ + 2 < 0.

Let t = 2ˣ, t > 0. Then t² − 3t + 2 < 0, so (t − 1)(t − 2) < 0, so 1 < t < 2. That is 2⁰ < 2ˣ < 2¹, so 0 < x < 1.

6. Solve √(x + 2) < x.

Need x + 2 ≥ 0 (x ≥ −2), x > 0, and x + 2 < x². The last gives x² − x − 2 > 0, so (x − 2)(x + 1) > 0, so x > 2 or x < −1. Join with x > 0: x > 2.

7. Solve √(x + 2) > x.

Road 1: x < 0 and x + 2 ≥ 0, so −2 ≤ x < 0. Road 2: x ≥ 0 and x + 2 > x², so x² − x − 2 < 0, so −1 < x < 2, so 0 ≤ x < 2. Join: −2 ≤ x < 2.

8. Solve log₂ x + log₂(x − 2) ≤ 3.

Domain: x > 0 and x − 2 > 0, so x > 2. Combine: log₂(x(x − 2)) ≤ 3, so x² − 2x ≤ 8, so x² − 2x − 8 ≤ 0, so (x − 4)(x + 2) ≤ 0, so −2 ≤ x ≤ 4. With the domain: 2 < x ≤ 4.

Common mistakes

Practice quiz

1. Solution of 5ˣ > 25 is:
2. Solution of (0.5)ˣ > 0.25 is:
3. log₃(x − 2) is defined for:
4. Solution of log₂ x < 3 is:
5. For √f < g we need f ≥ 0, f < g² and:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is the difference between an equation and an inequality here?

An equation gives one or a few points. An inequality gives whole stretches (intervals) of x, like x > 2.

Do I always flip the sign when I take logs?

No. Only if the base is between 0 and 1. For base 2, 10 or e the sign stays.

Which grade teaches this?

It appears in the last years of school (around Grade 11) in many countries, along with equations and function graphs.

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