What is the Doppler effect?
A wave has a frequency f (crests sent out per second) and a wavelength λ (the gap between crests). For sound, a high frequency sounds like a high pitch.
The Doppler effect is the change in frequency an observer notices when the source and the observer move toward or away from each other. Toward: higher frequency. Away: lower frequency. It is named after Christian Doppler, who described it in 1842.
The source itself does not change. The siren still makes the same note. Only what reaches you changes.
Why it happens: crests bunch up and spread out
Moving source
Sound moves through air at speed v (about 340 m/s). The source sends one crest every 1/f seconds. If the source moves forward at speed vs, it chases its own crests. Each new crest starts a little closer to the one before. So in front: λ′ = (v − vs) ÷ f, shorter. Behind: λ′ = (v + vs) ÷ f, longer. The speed of sound is unchanged, so the heard frequency f′ = v ÷ λ′ changes.
Moving observer
If the source is still but you move toward it at speed vo, the wavelength does not change, but you run into crests faster: f′ = f × (v + vo) ÷ v. Moving away gives f′ = f × (v − vo) ÷ v.
Only the motion along the line joining source and observer counts. A car passing at the side gives the biggest change just before and just after it passes.
The Doppler formula for sound
f′ = f × (v ± vo) ÷ (v ∓ vs)
- f = frequency sent out, f′ = frequency heard
- v = speed of sound in the medium (air ≈ 340 m/s)
- vo = speed of the observer, vs = speed of the source
Sign rule: use the sign that makes f′ bigger when they move closer. Top signs (+vo, −vs) for moving toward each other; bottom signs (−vo, +vs) for moving apart.
Check with the 3D: siren at 120 m/s, f = 500 Hz. In front f′ = 500 × 340 ÷ 220 ≈ 773 Hz. Behind f′ = 500 × 340 ÷ 460 ≈ 370 Hz.
Limits: if vs reaches v, crests pile up into a shock wave (the sonic boom of a jet). The formula also assumes still air; wind changes the result.
Doppler effect for light: red shift and blue shift
Light is a wave too. When a star or galaxy moves away from us, its light is stretched to longer wavelength: a red shift. Moving toward us: blue shift. For speeds much less than light speed c, the fractional change is Δλ ÷ λ ≈ v ÷ c. Astronomers use this to measure how fast stars move, to find planets that make their star wobble, and to show that distant galaxies are moving away (the expanding universe).
Applications of the Doppler effect
- Speed guns and radar: radio waves bounce off a car or a cricket ball; the change in frequency gives its speed.
- Weather radar: shows whether rain clouds move toward or away, and spots spinning storms.
- Medical ultrasound (Doppler scan): sound bounced off moving blood cells shows the speed and direction of blood flow and the baby's heartbeat.
- Bats and dolphins: hear the Doppler shift of their echoes to find moving prey.
- Satellites and GPS: frequency shift helps track satellites.
- Astronomy: red shift, blue shift and planet hunting.
Try it at home
Put a phone playing a steady beep (a tone generator app, 1000 Hz) in a sock and swing it in a circle on a string, safely away from people. A friend standing a few metres away hears the pitch go up and down every turn. Or stand by a road and listen to a horn as a vehicle passes. Predict first: when is the pitch highest?
Key formulas and definitions
- f′ = f × (v ± vo) ÷ (v ∓ vs) (top signs: moving toward each other)
- Source moving toward a still observer: f′ = f × v ÷ (v − vs)
- Source moving away: f′ = f × v ÷ (v + vs)
- Observer moving toward a still source: f′ = f × (v + vo) ÷ v
- Wavelength in front of a moving source: λ′ = (v − vs) ÷ f
- Light (v ≪ c): Δλ ÷ λ ≈ Δf ÷ f ≈ v ÷ c
Worked examples
1. An ambulance siren is 700 Hz. It drives toward you at 20 m/s. v = 340 m/s. What do you hear?
f′ = f × v ÷ (v − vs) = 700 × 340 ÷ 320 = 743.75 ≈ 744 Hz (higher).
2. The same ambulance now drives away at 20 m/s. What do you hear?
f′ = 700 × 340 ÷ 360 ≈ 661 Hz (lower).
3. You cycle at 10 m/s toward a still factory hooter of 510 Hz. v = 340 m/s.
f′ = f × (v + vo) ÷ v = 510 × 350 ÷ 340 = 525 Hz.
4. A 500 Hz source moves at 40 m/s toward you. Find the wavelength in front of it. v = 340 m/s.
λ′ = (v − vs) ÷ f = 300 ÷ 500 = 0.60 m. Without motion it would be 340 ÷ 500 = 0.68 m.
5. Before a train passes you hear its horn at 600 Hz; after it passes, 500 Hz. Find the train's speed. v = 340 m/s.
600 = f × 340 ÷ (340 − vs) and 500 = f × 340 ÷ (340 + vs). Divide: 600/500 = (340 + vs) ÷ (340 − vs). So 1.2(340 − vs) = 340 + vs → 408 − 1.2vs = 340 + vs → 68 = 2.2vs → vs ≈ 30.9 m/s.
6. A car (source, 400 Hz) and a bike (observer) move toward each other, car at 30 m/s, bike at 10 m/s. v = 340 m/s.
f′ = f × (v + vo) ÷ (v − vs) = 400 × 350 ÷ 310 ≈ 452 Hz.
Common mistakes
- Thinking the source really changes its note. The siren is the same; only the frequency reaching you changes.
- Thinking the speed of sound changes with the source's speed. The sound speed in the air stays v; the wavelength (or the meeting rate) changes.
- Mixing up signs. Always check: moving closer must give a bigger f′, moving apart a smaller f′.
- Thinking loudness causes it. A sound getting louder is not the Doppler effect; the Doppler effect is a change in pitch (frequency).