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Beats

When two sounds of slightly different frequencies f₁ and f₂ are heard together, they add by superposition. The loudness rises and falls regularly. Each rise is one beat. The number of beats per second is the beat frequency, f_beat = |f₁ − f₂|. Beats are used to tune musical instruments and to find an unknown frequency.

🎬 Step-by-step story

  1. Tuning fork 1 (blue) rings at 256 Hz. Its wave is steady: every crest is the same height.
  2. Tuning fork 2 (orange) rings at 260 Hz. It is also steady, just a little more crowded.
  3. Ring both together. The waves add. Sometimes crest meets crest (loud), sometimes crest meets trough (almost silent). The sound swells and fades.
  4. Count the loud moments in one second: 260 − 256 = 4. So the beat frequency is |f₁ − f₂|.
  5. Tuning a guitar: bring f₂ closer to 256. The beats slow down and vanish when f₂ = f₁. Now the notes match.
  6. Free play: set f₁ and f₂. First guess how many beats per second, then check with the counter.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why do we need two sounds for beats?

One steady sound has constant loudness. Beats come from two waves drifting in and out of step.

The two waves look almost the same. Why does it matter?

The small difference makes one slowly get ahead of the other, which is exactly what creates beats.

Why does the sound become almost silent at some moments?

At those moments a crest of one wave meets a trough of the other, and they cancel.

Why is the beat frequency f₁ − f₂ and not half of it?

The envelope cos(ω_b t) has frequency (f₁ − f₂)/2, but loudness peaks at both its + and − peaks, so twice per cycle.

How do musicians use beats?

They turn the peg until the beats get slower and stop. No beats = same frequency = in tune.

What are beats?

Play two sounds of nearly equal frequency together. You hear one tone whose loudness goes up and down again and again: loud, soft, loud, soft. This regular rise and fall of loudness is called beats. One loud-to-loud cycle is one beat.

Beats happen because of superposition in time: at one moment the two waves are in step and add (loud); a little later one has got half a cycle ahead and they cancel (soft).

Beat frequency: the maths

Take two waves of equal amplitude at one place:

s₁ = a cos(ω₁t), s₂ = a cos(ω₂t)

Using cos A + cos B = 2 cos((A − B)/2) cos((A + B)/2):

s = [2a cos(ω_b t)] cos(ω_a t), where ω_a = (ω₁ + ω₂)/2 and ω_b = (ω₁ − ω₂)/2.

f_beat = |f₁ − f₂|,   time for one beat = 1/|f₁ − f₂|.

Our ears can count beats only up to about 10 per second. Faster than that, they blend into a rough sound.

Uses of beats

The wax and file rule

Try it: beats with two phones

On two phones open any free tone-generator app. Set one to 440 Hz and the other to 443 Hz and play them side by side. Count the wobbles for 5 seconds: you should get about 15, so 3 per second. Now set the second one to 441 Hz: predict 1 beat per second, then check. In the 3D, step 5 lets you do the same with the sliders.

Key formulas and definitions

Worked examples

1. Two forks of 384 Hz and 380 Hz are sounded together. How many beats per second?

f_beat = 384 − 380 = 4 beats per second.

2. In the example above, what is the time between two loud sounds, and what pitch is heard?

Time = 1/4 = 0.25 s. Heard pitch = (384 + 380)/2 = 382 Hz.

3. A fork of 256 Hz gives 5 beats/s with an unknown fork. What can the unknown frequency be?

f = 256 ± 5, so 251 Hz or 261 Hz.

4. In the last example, the unknown fork is loaded with wax and the beats become 7 per second. Find its frequency.

Wax lowers the unknown frequency. If it were 261 Hz, lowering would bring it closer to 256 and beats would drop. Beats rose, so it was 251 Hz (now about 249 Hz, 7 beats).

5. Fork A gives 4 beats/s with a 320 Hz fork. When A is filed, the beats become 2 per second. Find A’s original frequency.

A is 316 or 324 Hz. Filing raises A. From 316 Hz it moves towards 320, so beats fall: fits. So A = 316 Hz.

6. Two strings of a sitar should both play 300 Hz, but 30 beats are counted in 10 s. What is the difference in their frequencies?

Beats per second = 30/10 = 3. So the frequencies differ by 3 Hz.

7. Two organ pipes give 5 beats/s when sounded together. One is an open pipe of length 0.5 m (v = 340 m/s). What can the other frequency be?

Open pipe f = v/2L = 340/1 = 340 Hz. The other is 340 ± 5 = 335 Hz or 345 Hz.

8. Wave equations: y₁ = a sin(600πt) and y₂ = a sin(608πt). Find the beat frequency.

f₁ = 600π/2π = 300 Hz, f₂ = 304 Hz. Beats = 4 per second.

Common mistakes

Practice quiz

1. Beat frequency of 440 Hz and 436 Hz is:
2. Beats are an example of:
3. Loading a tuning fork with wax:
4. If there are no beats, the two frequencies are:
5. The pitch heard during beats of f₁ and f₂ is about:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is beat frequency?

The number of loud-soft cycles per second when two close frequencies are heard together: f_beat = |f₁ − f₂|.

Why are beats not heard for a large frequency difference?

Our ears cannot pick out more than about 10 loudness changes per second, so large differences just sound rough.

What happens to frequency when wax is put on a tuning fork?

It decreases, because the prongs get heavier and vibrate more slowly.

Where this is taught

CBSE (India)Class 11Oscillations and Waves

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