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Trigonometric Ratios of Obtuse Angles (0° to 180°)

On a circle of radius 1, a point at angle θ has x = cos θ and y = sin θ. This works for every angle from 0° to 180°. Past 90° the point is on the left, so cos is negative. sin(180° − θ) = sin θ and cos(180° − θ) = −cos θ. tan θ = sin θ ÷ cos θ, and it is not defined at 90°.

🎬 Step-by-step story

  1. Draw a circle with radius 1. Put a point P on it at 40°. Its height is sin 40° and its sideways distance is cos 40°.
  2. Now swing P past 90°. The point moves to the left side. Sideways distance is now negative, so cos is negative. Height is still positive.
  3. Mirror P across the up-down axis. The new angle is 180° − θ. Height is the same, sideways flips sign. So sin stays and cos changes sign.
  4. Draw the orange line at x = 1. Where the radius line meets it, the height is tan. At 90° it never meets, so tan is not defined. After 90° it is negative.
  5. Walk through the key angles from 0° to 180°. Watch sin go up to 1 and back to 0, and cos slide from 1 to −1.
  6. Free play: slide the angle. Guess the signs of sin, cos and tan first, then check.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

How can a ratio of sides be negative? Lengths are never negative.

On the unit circle cos and sin are coordinates, not just lengths. A coordinate left of the y-axis is negative. For acute angles it matches the triangle rule.

Why is sin(180° − θ) equal to sin θ?

The two points are mirror images across the y-axis. A mirror keeps height the same and only flips left and right.

Why is tan 90° not defined?

The radius line is straight up and never meets the orange line. Also tan = sin ÷ cos and cos 90° = 0.

Why is sin 180° zero?

At 180° the point is at (−1, 0), on the x-axis. Its height is 0.

Is this different from the Class 10 ratios?

It is the same idea. For acute angles the answers match. The circle just lets us go past 90°.

Can I get all obtuse values from acute ones?

Yes. Use 180° − θ: sin stays, cos and tan change sign. Slide the angle to check.

Why we need ratios beyond 90°

In a right triangle, the other two angles are less than 90°. So sin, cos and tan were only defined for acute angles. But real triangles can have an obtuse angle (more than 90°). To measure them, we need sin, cos and tan for angles up to 180°.

The trick: use a circle of radius 1 with its centre at the origin. This is the unit circle. For an acute angle θ, a point P on the circle makes a small right triangle with the x-axis. Its height is sin θ and its base is cos θ. We keep exactly this idea and let θ grow past 90°.

Defining sin, cos and tan with the unit circle

Measure the angle θ from the positive x-axis, turning anticlockwise. Let P = (x, y) be the point on the circle.

For acute angles this gives the same answers as the right triangle. For 90° the point is at (0, 1): cos 90° = 0, sin 90° = 1, and tan 90° is not defined because we cannot divide by 0.

Signs and the mirror rule: 180° − θ

For an obtuse angle, P is on the left, so x is negative.

The point at 180° − θ is the mirror of the point at θ across the y-axis. So:

sin(180° − θ) = sin θ, cos(180° − θ) = −cos θ, tan(180° − θ) = −tan θ.

Use it to find any obtuse value from an acute one: sin 120° = sin 60° = √3/2; cos 120° = −cos 60° = −1/2; tan 120° = −tan 60° = −√3.

Values at 0°, 30°, 45°, 60°, 90°, 120°, 135°, 150°, 180°

θ0°30°45°60°90°120°135°150°180°
sin01/2√2/2√3/21√3/2√2/21/20
cos1√3/2√2/21/20−1/2−√2/2−√3/2−1
tan0√3/31√3–−√3−1−√3/30

Two useful facts: sin 0° = sin 180° = 0, and cos 180° = −1.

Try it

Open a door or a laptop lid. Stand it at 60°, then at 120°. Look at the tip from above: the height from the table is the same, but the tip is on the other side of the hinge. Now in the 3D, slide the angle to 60° and then 120° and compare sin and cos.

Key formulas and definitions

Worked examples

1. Find sin 135°.

sin 135° = sin(180° − 45°) = sin 45° = √2/2 ≈ 0.71.

2. Find cos 150°.

cos 150° = −cos(180° − 150°) = −cos 30° = −√3/2 ≈ −0.87.

3. Find tan 120°.

tan 120° = −tan 60° = −√3 ≈ −1.73. (Check: sin 120° ÷ cos 120° = (√3/2) ÷ (−1/2) = −√3.)

4. θ is between 0° and 180° and sin θ = √3/2. Find all possible θ.

sin 60° = √3/2. The mirror angle 180° − 60° = 120° has the same sin. So θ = 60° or 120°.

5. sin θ = 3/5 and θ is obtuse. Find cos θ and tan θ.

cos²θ = 1 − 9/25 = 16/25, so cos θ = ±4/5. For an obtuse angle cos is negative: cos θ = −4/5. tan θ = (3/5) ÷ (−4/5) = −3/4.

6. A triangle has two sides 6 cm and 8 cm and the angle between them is 150°. Find its area using ½ab sin C.

Area = ½ × 6 × 8 × sin 150° = 24 × ½ = 12 cm².

7. tan θ = −1 for 0° < θ < 180°. Find θ.

tan is negative, so θ is obtuse. tan 45° = 1, so θ = 180° − 45° = 135°.

Common mistakes

Practice quiz

1. cos 120° equals:
2. sin(180° − θ) equals:
3. Which ratio is not defined at 90°?
4. For an obtuse angle, tan is:
5. sin 180° equals:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What are the trigonometric ratios of obtuse angles?

They are sin, cos and tan for angles between 90° and 180°. We find them with the unit circle: cos is the x-coordinate (negative on the left) and sin is the y-coordinate.

Why is cos negative for obtuse angles?

Cos is the sideways distance of the point on the unit circle. Past 90° the point is to the left of the y-axis, so its x-coordinate is negative.

Is this topic in the school syllabus?

Yes. It is taught in the first year of upper secondary school in many countries (for example Japan, Grade 10 level) before the sine rule and cosine rule, and it also appears in Class 11 trigonometry.

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