Where the sine wave comes from
Take a point moving round a circle at a steady speed. Its height above the middle of the circle, measured against the angle it has turned, makes the sine wave y = sin x.
The wave repeats after every 2π. This repeat length is called the period. The highest value is 1 and the lowest is −1. Anything whose graph has this smooth up-and-down repeating shape is called sinusoidal.
Amplitude A: how tall
In y = A sin(ωx + φ), the number A multiplies the height. The wave now goes between −|A| and +|A|. The number |A| is the amplitude. Every y-value is multiplied by A, so the graph is stretched up and down. The zeros of the wave do not move.
Example: y = 3 sin x goes from −3 to 3.
ω: how fast, and the period
The number ω (omega, take ω > 0) tells how fast the angle grows. The wave repeats when ωx grows by 2π, so the period is T = 2π / ω. The frequency is how many waves fit in one unit: f = 1/T = ω / 2π.
Bigger ω squeezes the wave sideways, smaller ω stretches it. Example: y = sin 2x has period π; y = sin(x/2) has period 4π.
φ: the sideways shift (phase shift)
Write the inside as ωx + φ = ω(x + φ/ω). So the wave y = sin(ωx + φ) is the wave y = sin(ωx) moved by φ/ω units. If φ > 0 the graph moves to the left; if φ < 0 it moves to the right. This is the phase shift. The wave crosses zero going upward at x = −φ/ω.
You may also see a number added at the end: y = A sin(ωx + φ) + k. The +k lifts the whole wave up by k, so the middle line is y = k.
Drawing y = A sin(ωx + φ) from y = sin x
Do the changes one by one, starting from the basic wave y = sin x:
- Draw y = sin x.
- Squeeze it sideways so the period is 2π/ω. This gives y = sin ωx.
- Slide it left by φ/ω (right if φ is negative). This gives y = sin(ωx + φ).
- Stretch it up and down by A. This gives y = A sin(ωx + φ).
- Check the sketch: the maximum is A, the minimum is −A, and the first upward zero is at x = −φ/ω.
Using sine waves as models
Many repeating things are modelled by a sine wave. Ferris wheel: the height of a seat is h = centre height + radius · sin(...). Tides: water depth rises and falls about every 12 hours. AC electricity: the voltage V = V₀ sin(2πft); in India f = 50 Hz. Sound: a pure note is a sine wave; its amplitude is loudness and its frequency is pitch.
To build a model, read off A from the highest and lowest values, ω from the time of one repeat (ω = 2π / T), and φ from where the wave starts.
Try it at home
Tie a small stone to a string and swing it slowly in a circle. Ask a friend to stand in front and watch only the height of the stone. Count how many seconds one full turn takes: that is the period T. Then swing it in a bigger circle (bigger A) and faster (bigger ω) and see what changes. Predict first, then check on the 3D sliders.
Key formulas and definitions
- y = A sin(ωx + φ) (A > 0, ω > 0)
- Amplitude = |A|; range [−|A|, |A|]
- Period T = 2π / ω; frequency f = ω / 2π = 1/T
- Phase shift = φ / ω to the left (to the right if φ < 0)
- First upward zero at x = −φ / ω
- y = A sin(ωx + φ) + k has middle line y = k
Worked examples
1. For y = 3 sin 2x, find the amplitude, period and range.
A = 3, so the amplitude is 3. ω = 2, so T = 2π/2 = π. The range is −3 ≤ y ≤ 3.
2. For y = 2 sin(x + π/3), find the phase shift and where it crosses zero going upward.
ω = 1 and φ = π/3, so the shift is φ/ω = π/3 to the left. The period is 2π. The upward zero is at x = −φ/ω = −π/3.
3. Describe y = sin(2x − π/2).
Write 2x − π/2 = 2(x − π/4). So the wave is y = sin 2x shifted right by π/4. The period is π. The amplitude is 1.
4. A wave has maximum 5, minimum −5, period 4π and starts at 0 going up at x = 0. Write its equation.
A = 5. T = 4π gives ω = 2π/4π = 1/2. Starts at 0 going up, so φ = 0. The equation is y = 5 sin(x/2).
5. A Ferris wheel has radius 8 m. Its centre is 10 m above the ground. It takes 12 minutes for one turn, and a seat is at the lowest point at t = 0. Write the height h(t) and find h at t = 3 and t = 6.
A = 8, middle line k = 10. T = 12 so ω = 2π/12 = π/6. At the lowest point sin must be −1 at t = 0, so φ = −π/2. h(t) = 10 + 8 sin(πt/6 − π/2). At t = 3: sin(π/2 − π/2) = 0, so h = 10 m. At t = 6: sin(π − π/2) = 1, so h = 18 m.
6. The AC mains voltage is V = 325 sin(100πt) (t in seconds). Find the period, the frequency, and V at t = 0.005 s.
ω = 100π, so T = 2π/100π = 0.02 s. f = 1/T = 50 Hz. At t = 0.005: 100π × 0.005 = π/2, sin(π/2) = 1, so V = 325 volts (the peak).
7. In a simple model, the depth of water in a harbour is d = 5 + 2 sin(πt/6) metres (t in hours). Find the period, the highest and lowest depth, and the first time of high tide.
ω = π/6, so T = 2π ÷ (π/6) = 12 hours. Highest depth = 5 + 2 = 7 m and lowest = 5 − 2 = 3 m. High tide when sin = 1: πt/6 = π/2, so t = 3 hours.
Common mistakes
- Saying the period of sin(2x) is 2π × 2. It is 2π ÷ 2 = π. Bigger ω means a shorter period.
- Getting the direction of the shift wrong: sin(x + φ) moves LEFT for positive φ, not right.
- Forgetting to divide by ω: the shift of sin(2x + π) is π/2, not π.
- Thinking A changes the period. A only changes the height; ω changes the period.