Structure: how atoms are arranged
Atoms join by sharing or moving electrons. Each atom in a molecule keeps electron pairs (bonds and lone pairs) as far from each other as possible, because electron pairs repel. This simple idea (called VSEPR) gives the shape.
Common shapes
- Linear: CO2 (180 degrees).
- Bent: H2O (about 104.5 degrees), because two lone pairs push the bonds closer.
- Pyramid: NH3 (about 107 degrees), one lone pair.
- Tetrahedral: CH4 (109.5 degrees), four bonds, no lone pair.
Bigger structures follow the same ideas: a diamond is one giant network of carbon atoms, a salt crystal is a repeating grid of ions.
Properties: what shape and charge decide
Some atoms pull shared electrons harder; this pull is called electronegativity. If the pulls inside a molecule do not cancel, one end is slightly negative and the other slightly positive. The molecule is polar. If the pulls cancel, as in straight CO2 or tetrahedral CH4, the molecule is non-polar.
What this changes
- Polar molecules attract each other more, so water boils at 100 °C while methane boils near −162 °C.
- Like dissolves like: salt and sugar dissolve in water; oil does not.
- Giant networks (diamond, silica) are very hard and melt at very high temperatures; metals conduct because electrons move freely.
Energy: activation energy, heat and catalysts
To start a reaction, old bonds must first loosen. This needs a minimum push called the activation energy (Ea). Think of a ball that must climb a hill before it can roll down.
Heat of reaction
If the products are lower in energy than the reactants, heat is released (exothermic, ΔH negative). If they are higher, heat is taken in (endothermic, ΔH positive). ΔH does not depend on the hill height.
Catalysts
A catalyst gives the reaction an easier path with a lower hill. The reaction becomes faster, but the starting and ending energies, and so ΔH, do not change. A catalyst is not used up.
Equilibrium: when a reaction seems to stop
Many reactions are reversible: A ⇄ B. At the start only the forward reaction goes. As B builds up, the backward reaction speeds up. At equilibrium the two rates are equal, so the amounts of A and B stay constant. Nothing has stopped; both reactions still run (it is dynamic).
Equilibrium constant
For A ⇄ B, K = [B] / [A]. A large K means mostly products; a small K means mostly reactants. K changes only with temperature.
Le Chatelier's idea
If you disturb a system at equilibrium (add more A, change pressure or temperature), it shifts to reduce the disturbance. A catalyst does not shift the equilibrium; it only gets you there faster.
Try it: see polarity with a comb
Rub a plastic comb on dry hair. Open a tap so a thin stream of water falls. Bring the comb near the stream: the water bends towards it, because water molecules are polar. Now try the same with a thin stream of cooking oil: it barely moves. In the 3D, pick water and carbon dioxide in turn and compare the readout.
Key formulas and definitions
- Bond angles: CO2 180, NH3 about 107, H2O about 104.5, CH4 109.5 (degrees)
- Exothermic: products lower than reactants, dH < 0
- Endothermic: products higher than reactants, dH > 0
- For A <-> B: K = [B] / [A]
- At equilibrium: rate forward = rate backward
Worked examples
1. Why is carbon dioxide non-polar even though each C=O bond is polar?
CO2 is straight. The two bond pulls are equal and point in opposite directions, so they cancel. The molecule has no positive or negative end.
2. A reaction mixture at equilibrium has [A] = 0.2 mol/L and [B] = 0.6 mol/L for A <-> B. Find K.
K = [B] / [A] = 0.6 / 0.2 = 3. Products are favoured.
3. A catalyst lowers the activation energy from 80 kJ to 50 kJ. Reactants are 20 kJ above products. What is dH, and what is the new forward barrier?
dH = products minus reactants = -20 kJ (exothermic), and the catalyst does not change it. The new barrier is 50 kJ.
Common mistakes
- Thinking a catalyst changes the amount of product at equilibrium. It only changes how fast equilibrium is reached.
- Saying a reaction stops at equilibrium. Both forward and backward reactions continue at equal rates.
- Thinking polar bonds always make a polar molecule. Shape can cancel the pulls (CO2).
- Mixing up activation energy and dH. One is the hill height, the other is the difference between start and end.