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Population Genetics: Gene Pools, Hardy–Weinberg and New Species

Population genetics studies how allele frequencies change in a population. The gene pool is all alleles of all individuals. For one gene with alleles A and a, p + q = 1. If a population is large, mates randomly, and has no migration, mutation or selection, the Hardy–Weinberg principle says frequencies stay the same and genotypes are p² (AA) + 2pq (Aa) + q² (aa) = 1. Any change from this means evolution is happening, caused by genetic drift (bottleneck, founder effect), gene flow, mutation, natural selection or non-random mating. A species, in the biological species concept, is a group whose members can interbreed: a shared gene pool. New species form when gene pools are cut off by reproductive isolation: allopatric (geographic barrier) or sympatric (same area, e.g. polyploidy, habitat or behaviour). One ancestor can split into many forms (adaptive radiation, divergence), while unrelated groups can evolve similar shapes (convergence).

🎬 Step-by-step story

  1. A gene pool is all the alleles in a population. Count them: 12 blue A and 8 orange a out of 20. So p = 0.6 and q = 0.4.
  2. If mating is random, genotypes follow p² + 2pq + q² = 1. With p = 0.6: AA = 0.36, Aa = 0.48, aa = 0.16.
  3. This balance holds only if nothing changes the pool. Drift, gene flow, mutation, selection or non-random mating break it. Then evolution happens.
  4. Allopatric speciation: a river or mountain splits a population. The two groups change separately until they can no longer interbreed.
  5. Sympatric speciation happens in the same place (for example, polyploidy in plants). One ancestor can spread into many forms (adaptive radiation).
  6. Your turn: change p and watch the three genotype bars. Do they always add up to 1?

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why do we count alleles, not individuals?

Each diploid individual carries two copies, so an Aa person adds one A and one a. Counting beads shows this.

If A is dominant, won't it take over?

No. Dominance only hides a in Aa; it doesn't change how often A is passed on. Move the slider: the bars stay stable for any p.

Why does 2pq have a 2?

An Aa offspring can get A from the mother and a from the father, or the other way round: two ways.

Why is drift stronger in small populations?

With few individuals, chance matters more, like tossing a coin 5 times vs 1000 times.

Can new species form without a barrier?

Yes: sympatric speciation, e.g. a 4n plant cannot breed with 2n parents in the same field.

Do separated groups always become new species?

Only if reproductive isolation develops; if the barrier disappears early, they can mix again.

Gene pool and allele frequency

A population is a group of the same species living in one area and breeding together. Its gene pool is every allele of every gene in all its members.

Allele frequency = copies of that allele ÷ total copies of the gene. Each diploid individual has 2 copies.

Example: 10 plants: 4 AA, 4 Aa, 2 aa. Copies of A = 4×2 + 4 = 12; copies of a = 4 + 2×2 = 8; total = 20. So p = 12/20 = 0.6 and q = 0.4. Always p + q = 1.

In the biological species concept a species is a group of populations that can interbreed and produce fertile young, so a species shares one gene pool. (This concept does not fit asexual organisms or fossils well.)

The Hardy–Weinberg principle and calculations

In 1908 G. H. Hardy and Wilhelm Weinberg showed that in an ideal population allele and genotype frequencies stay constant generation after generation. Random mating is like drawing two alleles from the pool:

p² + 2pq + q² = 1 (AA + Aa + aa)

Five assumptions

  1. Very large population (no drift)
  2. Random mating
  3. No migration (no gene flow)
  4. No mutation
  5. No natural selection

Standard method

Start from the recessive phenotype, because aa individuals are the only ones you can recognise: q² = fraction showing the recessive trait → q = √q² → p = 1 − q → carriers = 2pq.

If observed genotype numbers differ clearly from p², 2pq, q², at least one assumption is broken and the population is evolving. A chi-square test is used to check if the gap is bigger than chance.

What changes allele frequencies

How new species form: speciation

Speciation is the splitting of one gene pool into two that can no longer mix. The key is reproductive isolation:

Allopatric speciation ("other homeland")

A geographic barrier (river change, mountain rise, sea level, island colonisation) separates populations. Mutation, drift and different selection make the gene pools drift apart. Example: squirrels on the two rims of a deep canyon.

Sympatric speciation ("same homeland")

New species form in the same area. Most often in plants by polyploidy: an error doubles chromosome sets (2n → 4n), and the 4n plant cannot make fertile offspring with 2n parents. Bread wheat arose by polyploidy. Animals may split by habitat or mate preference, such as cichlid fish in African lakes.

Adaptive radiation, divergence and convergence

Divergent evolution: related species become different as they adapt to different ways of life. They keep homologous structures (same origin, different use), like the forelimbs of human, whale and bat.

Adaptive radiation is fast divergence from one ancestor into many niches: Darwin's finches in the Galápagos (seed-crushing, insect-eating beaks) or Australian marsupials.

Convergent evolution: unrelated species evolve similar features because they face similar problems. These are analogous structures (different origin, same use): wings of bird and insect, streamlined bodies of shark and dolphin, eyes of octopus and human.

Key formulas and definitions

Worked examples

1. In a population of 500 people, 320 are AA, 160 are Aa and 20 are aa. Find p and q.

Copies of A = 2×320 + 160 = 800. Total copies = 2×500 = 1000. p = 800/1000 = 0.8. q = 1 − 0.8 = 0.2. (Check: copies of a = 160 + 2×20 = 200 → 0.2.)

2. Is the population above in Hardy–Weinberg equilibrium?

Expected AA = p² × 500 = 0.64 × 500 = 320; Aa = 2pq × 500 = 0.32 × 500 = 160; aa = q² × 500 = 0.04 × 500 = 20. Observed equals expected, so yes, it is in equilibrium.

3. Albinism (recessive) appears in 1 out of 400 people in a region. What fraction are carriers?

q² = 1/400 = 0.0025 → q = 0.05. p = 0.95. Carriers = 2pq = 2 × 0.95 × 0.05 = 0.095, about 9.5% (roughly 1 in 10).

4. In a flock of 1,000 sheep, 90 have black wool (recessive bb). How many are expected to be heterozygous?

q² = 90/1000 = 0.09 → q = 0.3, p = 0.7. 2pq = 2 × 0.7 × 0.3 = 0.42 → 0.42 × 1000 = 420 heterozygous sheep.

5. Next generation the same flock has p = 0.75. What does this tell you?

p changed from 0.7 to 0.75, so allele frequencies are not constant: at least one Hardy–Weinberg assumption is broken (for example farmers choosing white sheep = selection). The population is evolving.

6. A storm leaves only 5 birds of a large island population; 4 carry only allele R. Why might R become fixed even if it gives no advantage?

This is a bottleneck. With so few individuals, chance decides which alleles pass on (genetic drift). R starts at a high frequency (about 0.8 or more), so by chance it may reach 1.0 (fixed) while other alleles are lost, without any selection.

Common mistakes

Practice quiz

1. In p² + 2pq + q² = 1, the term 2pq stands for:
2. If q² = 0.25, then p is:
3. Which is NOT a Hardy–Weinberg assumption?
4. A new species forming after a river splits a population is:
5. Wings of a bat and a butterfly are an example of:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is the Hardy–Weinberg equation?

p² + 2pq + q² = 1, where p and q are allele frequencies and the three terms are the AA, Aa and aa frequencies.

What are the 5 conditions of Hardy–Weinberg equilibrium?

A very large population, random mating, no migration, no mutation and no natural selection.

What is the difference between allopatric and sympatric speciation?

Allopatric happens when a physical barrier separates populations; sympatric happens in the same area, often by polyploidy or behaviour.

Where this is taught

NetherlandsHAVO 4 (bovenbouw, 2e fase)Life
NetherlandsVWO 4 (bovenbouw, 2e fase)Life
NetherlandsVWO 6 (eindexamenjaar)Evolution
PolandLiceum ogólnokształcące, klasa IVXVI. Evolution
USA (Common Core, NGSS, AP)Grade 11Natural Selection
China高一Comp.2 Ch.6 Evolution

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