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Refraction, Total Internal Reflection and the Prism

Light bends when it crosses from one medium to another: n₁ sin i = n₂ sin r. Going from a denser to a rarer medium it bends away from the normal; beyond the critical angle C (sin C = 1/n) no light escapes and all of it reflects back: total internal reflection. Optical fibres use this to carry light. In a prism, r₁ + r₂ = A and deviation δ = i + e − A; at minimum deviation n = sin((A + δm)/2) / sin(A/2).

🎬 Step-by-step story

  1. Light goes from air into glass. At the surface it bends towards the normal (the green line). The angle inside, r, is smaller.
  2. Now the light starts inside the glass and goes out into air. It bends away from the normal. We slowly tilt the ray. At one special angle, the ray just skims the surface. This is the critical angle.
  3. Tilt a little more. Now no light gets out at all. Every bit bounces back inside. This is total internal reflection.
  4. An optical fibre is a thin glass thread. Light hits its wall at a big angle every time, so it bounces inside and travels far, even around bends.
  5. A prism bends light twice. Watch the deviation δ as the ray tilts: it falls, stops at a smallest value, then rises again. That smallest value is the minimum deviation.
  6. Free play. Pick a scene, change the angle and the refractive index. Guess first, then check.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why does light bend at all when it enters glass?

Light slows down in glass. The side of the beam that enters first slows first, so the whole beam turns, like a car turning when one wheel hits sand.

Why is there a special 'critical' angle?

Going into air, r is always bigger than i. As i grows, r hits 90° first. That i is the critical angle; beyond it, Snell's law would need sin r > 1, which is impossible.

Is some light also reflected before TIR?

Yes. Below C, most light refracts out and a little reflects back (the faint ray). At and beyond C, all of it reflects.

Why does TIR not happen when light enters glass from air?

Going into a denser medium, r is always smaller than i, so r can never reach 90°. There is no critical angle on that side.

How does light follow a bent optical fibre?

As long as the bend is gentle, the light still hits the wall at more than the critical angle, so it keeps bouncing inside along the curve.

Why does a prism have a minimum deviation?

At small i the first face bends little but the second face bends a lot; at large i it is the other way round. When the ray goes through symmetrically, the total turn is least.

Refraction and Snell's law

Refraction is the bending of light when it goes from one medium into another, because its speed changes. The refractive index n of a medium tells how much slower light is there: n = c / v. Air has n ≈ 1, water 1.33, glass about 1.5, diamond 2.42.

Snell's law: n₁ sin i = n₂ sin r. Here i is the angle in the first medium and r in the second, both from the normal. Also, the incident ray, refracted ray and normal lie in one plane.

The relative refractive index of medium 2 with respect to medium 1 is n₂₁ = n₂/n₁ = v₁/v₂. Note n₁₂ = 1/n₂₁.

Apparent depth

A coin at the bottom of a bucket of water looks raised. Rays from the coin bend away from the normal as they leave the water, and your eye traces them back to a higher point. When you look straight down:

n = real depth / apparent depth

The coin seems raised by d(1 − 1/n). For water, a 40 cm deep coin looks about 30 cm deep. The same bending lifts the Sun: we see it for about 2 minutes before real sunrise and after real sunset.

Total internal reflection

When light goes from a denser to a rarer medium, r is bigger than i. As i grows, r reaches 90° first. The angle i at which this happens is the critical angle C. Put r = 90° in Snell's law (n₁ = n, n₂ = 1):

sin C = 1/n (more generally sin C = n₂/n₁)

If i > C, no refracted ray can exist, so all the light reflects back into the denser medium. This is total internal reflection (TIR). Two conditions are needed:

  1. Light must travel from a denser to a rarer medium.
  2. The angle of incidence must be larger than the critical angle.

For glass (n = 1.5), C ≈ 41.8°; for water, C ≈ 48.8°; for diamond, C ≈ 24.4°. TIR reflects 100% of the light, better than any silvered mirror.

Optical fibres

An optical fibre is a very thin glass or plastic thread. Its core has a higher refractive index than the cladding around it. Light entering one end hits the core–cladding wall at an angle larger than C, so it undergoes TIR again and again and comes out at the far end with very little loss, even if the fibre bends gently.

Uses: internet and phone signals (a bundle carries huge data), endoscopes in hospitals, decorative lamps. Other TIR uses: sparkling of diamonds, totally reflecting prisms in binoculars and periscopes (turning light by 90° or 180°), and mirages.

Refraction through a prism

A prism has two flat refracting faces meeting at the angle of the prism A. A ray enters with angle i, bends to r₁, meets the second face at r₂ and leaves at angle e. The total turning of the ray is the angle of deviation δ.

Step 1: the angles inside

The two normals and the prism faces make a four-sided figure, which gives r₁ + r₂ = A.

Step 2: deviation

The ray turns by (i − r₁) at the first face and (e − r₂) at the second. So δ = (i − r₁) + (e − r₂) = i + e − (r₁ + r₂), giving δ = i + e − A.

Step 3: minimum deviation

As i increases, δ first decreases, reaches a smallest value δm, then increases. At δm the ray passes through the prism symmetrically: i = e and r₁ = r₂ = A/2. Then i = (A + δm)/2, so

n = sin((A + δm)/2) / sin(A/2)

Thin prism

For a small A (a few degrees), sin x ≈ x, so δ = (n − 1)A. Deviation does not depend on i for a thin prism.

Try it: make light disappear

Fill a clear glass with water and hold it a little above your eye level. Look up at the water surface from below, through the side. At a steep angle the surface shines like silver: that is total internal reflection. Or shine a phone torch into a stream of water flowing from a bottle hole in a dark room: the light follows the curved stream like a fibre. In the 3D, predict the angle where the ray stops leaving the glass, then tilt it to check.

Key formulas and definitions

Worked examples

1. Light enters glass (n = 1.5) from air at 45°. Find the angle of refraction.

Step 1: 1 × sin 45° = 1.5 × sin r. Step 2: sin r = 0.707/1.5 = 0.471. Step 3: r ≈ 28.1°. It bends towards the normal.

2. Find the speed of light in water (n = 1.33).

Step 1: v = c/n. Step 2: v = 3 × 10⁸ / 1.33. Step 3: v ≈ 2.26 × 10⁸ m/s.

3. A coin lies at the bottom of a tank of water 24 cm deep (n = 4/3). How deep does it appear from above?

Step 1: apparent depth = real depth / n. Step 2: = 24 ÷ (4/3) = 18 cm. Step 3: the coin looks raised by 6 cm.

4. Find the critical angle for glass of refractive index 1.5.

Step 1: sin C = 1/n = 1/1.5 = 0.667. Step 2: C = sin⁻¹(0.667) ≈ 41.8°. So any ray inside glass hitting the surface at more than 41.8° is totally reflected.

5. The critical angle for a medium is 30°. Find its refractive index and the speed of light in it.

Step 1: n = 1/sin C = 1/0.5 = 2. Step 2: v = c/n = 1.5 × 10⁸ m/s.

6. Light goes from glass (n = 1.5) to water (n = 1.33). Find the critical angle at the glass–water surface.

Step 1: sin C = n₂/n₁ = 1.33/1.5 = 0.887. Step 2: C ≈ 62.5°. It is larger than for glass–air because water is closer to glass in n.

7. A prism of angle 60° gives minimum deviation 30°. Find its refractive index.

Step 1: n = sin((A + δm)/2) / sin(A/2). Step 2: = sin 45° / sin 30° = 0.707/0.5. Step 3: n ≈ 1.414 (= √2).

8. A ray falls on a prism (A = 60°, n = √2). At minimum deviation, find r₁, the angle of incidence and δm.

Step 1: at δm, r₁ = r₂ = A/2 = 30°. Step 2: sin i = n sin r₁ = √2 × 0.5 = 0.707, so i = 45°. Step 3: i = e, so δm = 2i − A = 90° − 60° = 30°.

9. A thin prism of angle 5° and n = 1.6 is placed in air. Find the deviation. What if it is dipped in water (n = 1.33)?

Step 1: in air δ = (n − 1)A = 0.6 × 5° = 3°. Step 2: in water use the relative index n = 1.6/1.33 ≈ 1.2. Step 3: δ = 0.2 × 5° = 1°. The deviation becomes smaller in water.

Common mistakes

Practice quiz

1. The critical angle C and refractive index n (denser medium to air) are related by:
2. Total internal reflection needs light to go from:
3. Optical fibres work on the principle of:
4. For a prism, the angle of deviation is:
5. At minimum deviation in a prism:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is the relation between critical angle and refractive index?

sin C = 1/n for light going from a medium of index n into air. A larger n gives a smaller critical angle.

What are the two conditions for total internal reflection?

Light must go from a denser to a rarer medium, and the angle of incidence must be more than the critical angle.

What is the formula for the refractive index of a prism?

n = sin((A + δm)/2) / sin(A/2), where A is the prism angle and δm is the angle of minimum deviation.

Where this is taught

CBSE (India)Class 12Optics
South Korea고등학교 3학년Waves and communication
China高二Selective 1 Ch.4 Light

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