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Rational Equations

A rational (fractional) equation has the unknown in the denominator of a fraction. First write the banned values that make any denominator zero. Then multiply every term by the lowest common denominator (LCD) to clear the fractions, and solve the equation that is left (often linear or quadratic). Finally check each root: a root that is a banned value is extraneous and is thrown out. The same method solves rate problems such as boats on rivers and people working together.

🎬 Step-by-step story

  1. Here x is in the bottom of a fraction. A bottom can never be 0. So x = 1 and x = −1 are banned. They stand as red gates on the number line.
  2. Multiply every term by the LCD, (x − 1)(x + 1). All the bottoms cancel. What is left is a normal equation with no fractions.
  3. Solve it. x² + x − 2 = 0 factorises to (x + 2)(x − 1) = 0. Two roots drop onto the line: x = −2 and x = 1.
  4. Now check. x = 1 lands on a red gate, so we throw it out. It is called an extraneous root. The only answer is x = −2.
  5. A boat goes 12 km up a river and back. The river flows at 2 km/h. Time = distance ÷ speed. Slide the speed until the trip takes 2.5 hours.
  6. Free play: pick an equation and press Next line. Watch the gates, the roots and the check, one line at a time.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why can't the bottom be zero?

Division by zero has no answer: no number times 0 gives 4. So any x that makes a bottom 0 is not allowed. The red gates show these values.

Why do I multiply every term, even plain numbers?

Both sides must stay equal. If you multiply only some terms, you change the equation. In the 3D every fraction is multiplied and all bottoms cancel at once.

Where did x = 1 come from if it is not allowed?

It is a root of the cleared equation, not of the original. Multiplying by the LCD, which is 0 at x = 1, added it.

Do I really need to check?

Yes. The check is how you catch extraneous roots. In the 3D the root that lands on a gate falls away.

Why is upstream speed v − 2?

The river pushes against the boat when it goes up, taking away 2 km/h; going down it adds 2 km/h. Watch the boat move slowly left and quickly right.

Can a rational equation have no solution?

Yes. If every root of the cleared equation is banned, nothing is left. Pick the fourth equation in free play to see it.

What is a rational equation?

A rational equation (also called a fractional equation) has the unknown in the denominator (bottom) of at least one fraction. Examples: 3/x = 1/(x − 4) and x/(x + 1) + 2/(x − 1) = 4/(x² − 1).

Not rational: x/3 + x/5 = 8, because the bottoms are just numbers. That is an ordinary linear equation.

Banned values (the domain)

Division by zero has no meaning. So any value of x that makes a denominator zero is not allowed. Find them first. For x/(x + 1) + 2/(x − 1) = 4/(x² − 1), the banned values are x = −1 and x = 1. The allowed values form the domain of the equation.

How to solve: Gate, Clear, Solve, Check

  1. Gate: factorise every denominator and write the banned values.
  2. Clear: multiply every term on both sides by the LCD. All the bottoms cancel.
  3. Solve the equation that is left. It is usually linear or quadratic.
  4. Check: remove any root that is a banned value. Write the answer.

Worked: x/(x + 1) + 2/(x − 1) = 4/(x² − 1). Since x² − 1 = (x − 1)(x + 1), the LCD is (x − 1)(x + 1). Multiply: x(x − 1) + 2(x + 1) = 4 → x² + x − 2 = 0 → (x + 2)(x − 1) = 0. Roots −2 and 1. But 1 is banned. Answer: x = −2.

Shortcut for one fraction on each side

If a/b = c/d, you may cross-multiply: ad = bc. Still check the banned values.

Special case: a fraction equal to zero

A/B = 0 exactly when A = 0 and B ≠ 0. Example: (x² − 9)/(x − 3) = 0 gives x = ±3, but x = 3 is banned, so x = −3.

Equivalent equations and extraneous roots

Two equations are equivalent if they have exactly the same solutions. Adding the same number to both sides, or multiplying by a non-zero number, keeps an equation equivalent.

Multiplying by an expression with x (like the LCD) is different. For some x the expression is 0, and multiplying by 0 can make a false statement look true. So the new equation may have an extra root that the original does not have. Such a root is called extraneous (outside). That is why the check step is not optional.

An equation can even have no solution: 1/(x − 1) + 1/(x + 1) = 2/(x² − 1) leads to 2x = 2, x = 1, which is banned.

Equations reducible to quadratics

Some equations become quadratic after a clever substitution.

Word problems with rates

Use time = distance ÷ speed and work rate = 1 ÷ time.

Boat and river

Boat speed in still water v km/h, river current 2 km/h. Upstream speed v − 2, downstream speed v + 2. If 12 km up and 12 km back takes 2.5 h: 12/(v − 2) + 12/(v + 2) = 2.5. Clear: 12(v + 2) + 12(v − 2) = 2.5(v² − 4) → 5v² − 48v − 20 = 0 → (5v + 2)(v − 10) = 0. v = 10 km/h (v = −0.4 makes no sense for a speed).

Working together

If A takes a hours and B takes b hours, together they do 1/a + 1/b of the job per hour. Time together t satisfies 1/a + 1/b = 1/t.

Always check that the answer makes sense in the story: speeds positive, times positive, numbers of people whole.

Key formulas and definitions

Worked examples

1. Solve 6/x = 2.

Banned: x ≠ 0. Multiply by x: 6 = 2x, so x = 3. 3 is allowed. Answer x = 3.

2. Solve 3/x = 1/(x − 4).

Banned: 0 and 4. Cross-multiply: 3(x − 4) = x → 3x − 12 = x → 2x = 12 → x = 6. Allowed. Answer x = 6.

3. Solve (x + 3)/(x − 1) = 2.

Banned: 1. Multiply by (x − 1): x + 3 = 2x − 2 → x = 5. Check: 8/4 = 2 ✓. Answer x = 5.

4. Solve x²/(x − 2) = 4/(x − 2).

Banned: 2. Multiply by (x − 2): x² = 4 → x = 2 or −2. x = 2 is banned (extraneous). Answer x = −2.

5. Solve x/(x + 1) + 2/(x − 1) = 4/(x² − 1).

Banned: ±1. LCD (x − 1)(x + 1). x(x − 1) + 2(x + 1) = 4 → x² + x − 2 = 0 → (x + 2)(x − 1) = 0. x = 1 is banned. Answer x = −2.

6. Solve 1/x + 1/(x + 2) = 4/3.

Banned: 0, −2. LCD 3x(x + 2). 3(x + 2) + 3x = 4x(x + 2) → 6x + 6 = 4x² + 8x → 4x² + 2x − 6 = 0 → 2x² + x − 3 = 0 → (2x + 3)(x − 1) = 0. x = 1 or x = −3/2, both allowed.

7. Solve x⁴ − 13x² + 36 = 0.

Put t = x²: t² − 13t + 36 = 0 → (t − 4)(t − 9) = 0. x² = 4 → x = ±2; x² = 9 → x = ±3. Four roots: ±2, ±3.

8. A pipe fills a tank in 3 h, another in 6 h. How long do both take together?

1/3 + 1/6 = 1/t → 2/6 + 1/6 = 3/6 = 1/2 → t = 2 hours.

Common mistakes

Practice quiz

1. Which value is banned in 5/(x − 3) = 2?
2. The LCD of 1/(x − 2) and 3/(x² − 4) is:
3. An extraneous root is a root that:
4. The solution of 4/x = 2/(x − 1) is:
5. To solve x⁴ − 10x² + 9 = 0 we put:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

How do you solve rational equations?

Write the banned values, multiply every term by the LCD to clear the fractions, solve the resulting equation, and reject any root that makes a denominator zero.

What is an extraneous solution?

A value that solves the cleared equation but not the original, usually because it makes a denominator zero.

What is an equation reducible to a quadratic?

An equation that becomes quadratic after a substitution, for example x⁴ − 5x² + 4 = 0 with t = x².

Where this is taught

Ukraine8 класEquations
Russia8 классEquations and inequalities
China八年级(初二)Ch.18 Fractional expressions

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