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Clock and Calendar: Telling Time by the Sky and by Numbers

Our time units come from the sky. One spin of the Earth relative to the Sun is a solar day (24 h); relative to the stars it is a sidereal day (about 23 h 56 min). The Moon's phases repeat every 29.53 days (a month). The Earth goes round the Sun in about 365.2422 days (a year). Calendars are lunar, solar or lunisolar. The Gregorian leap year rule keeps the calendar in step with the seasons. With numbers we can then solve clock problems (angle = |30H − 5.5M|) and calendar problems (odd days).

🎬 Step-by-step story

  1. The Earth spins. The red pin starts facing the Sun. After one full turn it faces the Sun again. That is one solar day: 24 hours.
  2. But the Earth also moves along its path round the Sun. After one turn against a far star (23 h 56 min), the pin is not yet facing the Sun. It needs a little extra turn, about 4 minutes. Solar day = sidereal day + 4 min.
  3. The Moon goes round the Earth: its phases repeat every 29.5 days, a month. The Earth goes once round the Sun in 365.2422 days, a year. The extra 0.2422 day is why we need leap years.
  4. Now a clock. At 3:00 the hands make 90°. As the minutes run, the minute hand moves 6° each minute and the hour hand only 0.5°. At 3:40 the angle is 130°.
  5. A week has 7 days. A normal year has 365 days = 52 weeks + 1 day. That 1 extra day is an 'odd day'. So 1 January moves one weekday forward: Wednesday in 2025, Thursday in 2026.
  6. Your turn. Drag the time slider to see the angle between the hands. Type any year to see if it is a leap year and what day 1 January falls on.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why does a day have 24 hours?

It is the time from the Sun overhead to the Sun overhead again, as the pin shows when it faces the Sun after one full turn.

Why is the sidereal day 4 minutes shorter?

In step 2 the Earth moves along its orbit while turning, so after one turn against the star it must turn a bit more to face the Sun.

Why do we need leap years at all?

The year is 365.2422 days, not 365. Without a leap day, the calendar would slip about 1 day every 4 years against the seasons.

Why is the angle at 3:30 not 90°?

The hour hand also moves: by 3:30 it is halfway to 4. Watch it creep forward in step 4.

Why does my birthday move one weekday each year?

365 days is 52 weeks plus 1 extra day, so the weekday shifts by one (by two if 29 February is in between).

Time from the sky: day, month and year

People measured time by watching the sky long before clocks.

These numbers do not divide each other neatly. That is the whole problem of making a calendar.

Solar day and sidereal day

A sidereal day is one turn of the Earth measured against a far star: about 23 h 56 min 4 s. During that time the Earth has also moved about 1° along its orbit, so it must turn a little more (about 4 minutes) before the Sun is overhead again. So the solar day is about 24 h.

This is why a given star rises about 4 minutes earlier every night.

Time zones

The Earth turns 360° in 24 h, so 15° of longitude = 1 hour, and 1° = 4 minutes. Countries use time zones counted from UTC (Greenwich, 0°). India uses UTC+5:30 (82.5° E).

Types of calendars

Julian and Gregorian

The Julian calendar (46 BCE) added a leap day every 4 years: year = 365.25 days. That is 11 minutes too long, so by 1582 the calendar was 10 days off. The Gregorian reform dropped 10 days and changed the rule:

A year is a leap year if it divides by 4, except century years, which must divide by 400. So 2024 and 2000 are leap years; 1900 and 2100 are not. Average year = 365.2425 days, very close to 365.2422.

Clock problems: angle between the hands

The minute hand turns 360° in 60 min: 6° per minute. The hour hand turns 30° in 60 min: 0.5° per minute.

At H hours and M minutes:

Angle = |30H − 5.5M| (if it is more than 180°, take 360° minus it).

The minute hand gains 5.5° per minute on the hour hand. The hands overlap 11 times in 12 hours (every 65 5/11 minutes) and are opposite 11 times in 12 hours.

Calendar problems: odd days

Odd days are the days left over after full weeks.

To move from one date to another, add up the odd days and move that many weekdays forward. Example: 1 Jan 2025 was a Wednesday. 2025 is common, so 1 Jan 2026 is Wednesday + 1 = Thursday.

Try it

Look at a wall calendar. Find your birthday's weekday this year. Predict next year's using odd days (+1, or +2 if 29 February comes in between). Check with the 3D year box.

Key formulas and definitions

Worked examples

1. Find the angle between the hands at 4:20.

|30 × 4 − 5.5 × 20| = |120 − 110| = 10°.

2. Find the angle between the hands at 9:30.

|270 − 165| = 105°.

3. Is 2100 a leap year?

It divides by 4, but it is a century year and 2100 ÷ 400 is not whole. So it is not a leap year.

4. 1 January 2024 was a Monday. What day was 1 January 2025?

2024 is a leap year: 2 odd days. Monday + 2 = Wednesday.

5. A place is at 45° E. Its local sun time is how far ahead of Greenwich?

45 × 4 min = 180 min = 3 hours ahead.

6. At what time between 2 and 3 o'clock are the hands together?

At 2:00 the minute hand is 60° behind. It gains 5.5° per minute: 60 ÷ 5.5 = 10 10/11 min. So at about 2:10:55.

Common mistakes

Practice quiz

1. One turn of the Earth measured against a far star is the:
2. Which year is a leap year?
3. Angle between the hands at 6:00:
4. Odd days in a common year:
5. A calendar that adds an extra month sometimes to match the seasons is:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is the formula for the angle between clock hands?

Angle = |30H − 5.5M|; if it is above 180°, subtract it from 360°.

How do I know if a year is a leap year?

It must divide by 4. Century years (like 1900, 2000) must divide by 400.

What is an odd day?

A day left over after counting full weeks. A common year has 1 odd day, a leap year has 2.

Where this is taught

Ukraine11 класCelestial sphere and motion of celestial bodies
CBSE (India)Class 11Numbers, Quantification and Numerical Applications

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