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Polarisation of Light

Light is a transverse wave: its electric field shakes at right angles to the direction it travels. In ordinary light the shaking happens in all directions. A polaroid lets through only one direction, so the light becomes plane polarised and half as bright. A second polaroid at angle θ lets through I = I₀cos²θ (Malus's law). Polarisation proves light is transverse and is used in sunglasses, LCD screens, cameras and 3D films.

🎬 Step-by-step story

  1. A lamp sends out ordinary light. The orange arrows show how its electric field shakes. They point in every direction, all round the beam. This is unpolarised light.
  2. Now light passes through Polaroid 1. Its slits allow only up–down shaking. After it, all blue arrows point the same way. The light is now plane polarised and half as bright.
  3. Polaroid 2 is added, lined up with Polaroid 1 (θ = 0°). Everything that passed the first one also passes the second. The screen stays at ½ I₀.
  4. Polaroid 2 turns slowly to 60°. The green arrows get shorter and the screen gets dimmer. Only the part along the new slits gets through: I = ½ I₀ cos²θ.
  5. At θ = 90° the two polaroids are "crossed". No green arrows, the screen goes dark. This can only happen if light is a transverse wave.
  6. Your turn: move the angle slider from 0° to 180°. Watch the brightness fall to zero at 90° and come back at 180°.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why does one polaroid always cut unpolarised light to exactly half?

Unpolarised light shakes equally in all directions. On average cos²θ over all angles is ½, so half the energy passes whatever way the polaroid faces.

Why does the light not dim when the second polaroid is lined up?

All of the light is already shaking along the pass axis, so cos 0° = 1 and everything gets through.

Why cos² and not cos?

The field part that gets through is E cosθ. Brightness (intensity) depends on the square of the field, so it becomes cos²θ.

Where does the blocked light go?

A polaroid absorbs it and turns it into a tiny bit of heat.

Why does the screen come back bright at 180°?

Turning a pass axis by 180° gives the same line again, so cos²180° = 1.

What is polarisation?

Light is an electromagnetic wave. Its electric field E shakes at right angles to the direction of travel, so light is a transverse wave.

In unpolarised light (sun, bulb, candle) the direction of shaking keeps changing at random. In plane polarised light the field shakes in only one plane. Changing unpolarised light into polarised light is called polarisation.

Only transverse waves can be polarised. Sound in air is longitudinal, so it cannot be polarised. This is the strongest proof that light is transverse.

Polaroids and Malus's law

A polaroid is a thin plastic sheet with long molecules lined up in one direction. It passes the part of E along its pass axis and absorbs the rest.

Why squared? The amplitude that passes is E cosθ, and intensity depends on amplitude squared.

Crossed polaroids

At θ = 90°, cos 90° = 0, so no light passes. Turning the analyser once round gives two bright and two dark positions.

Polarisation by reflection and scattering

When light reflects from glass or water, the reflected light is partly polarised. At one special angle, the Brewster angle θB, it is fully polarised and the reflected and refracted rays are at 90° to each other. Brewster's law: tan θB = n (refractive index). For glass, n = 1.5 gives θB ≈ 56°; for water, n = 1.33 gives about 53°.

Sunlight scattered by air molecules is also partly polarised, strongest at 90° from the Sun. Bees use this to find direction.

Uses of polarisation

Try it at home

Look at a phone or laptop screen through polarised sunglasses and slowly rotate the glasses. Note the angle at which the screen looks darkest. That is 90° between the screen's polariser and the glasses.

Key formulas and definitions

Worked examples

1. Unpolarised light of intensity 80 W m⁻² falls on a polaroid. What comes out?

One polaroid passes half: I = 80 / 2 = 40 W m⁻².

2. Polarised light of 40 W m⁻² meets an analyser at 60°. Find the intensity.

cos 60° = 0.5, cos² 60° = 0.25. I = 40 × 0.25 = 10 W m⁻².

3. Unpolarised light I₀ passes two polaroids at 45°. What fraction comes out?

After first: I₀/2. After second: (I₀/2) × cos²45° = (I₀/2) × ½ = I₀/4. So one quarter.

4. Find the Brewster angle for water (n = 1.33).

tan θ_B = 1.33 → θ_B = tan⁻¹(1.33) ≈ 53°.

5. Three polaroids: first and last are crossed, the middle is at 45° to both. Unpolarised I₀ enters. Find the output.

After 1st: I₀/2. After 2nd (45°): I₀/2 × ½ = I₀/4. After 3rd (45° to 2nd): I₀/4 × ½ = I₀/8. Light gets through even though 1st and 3rd are crossed!

6. At what angle should the analyser be set so that the intensity is 75% of the polarised light falling on it?

cos²θ = 0.75 → cosθ = 0.866 → θ = 30°.

Common mistakes

Practice quiz

1. Polarisation shows that light is:
2. Unpolarised light of intensity I₀ passes one polaroid. Output:
3. Malus's law is:
4. Two polaroids are crossed. The light through them is:
5. Brewster's law is:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is polarisation of light in simple words?

It is making light shake in only one direction instead of all directions, usually with a polaroid filter.

What is Malus's law?

When polarised light of intensity I₁ passes an analyser at angle θ, the intensity that comes out is I₁cos²θ.

Why do polarised sunglasses reduce glare?

Glare reflected from roads and water is mostly polarised sideways; the glasses only pass up–down shaking, so they block it.

Where this is taught

PolandLiceum ogólnokształcące, klasa IIIWaves and optics
South Korea고등학교 2학년Light and communication
China高二Selective 1 Ch.4 Light

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