Direct and indirect measurement
A direct measurement reads the quantity on an instrument: length with a ruler, time with a stopwatch, mass on a balance. An indirect measurement finds a quantity from a formula using direct readings. g is found from L and T, density from mass and volume, resistance from V and I.
The least count is the smallest division of an instrument (a ruler: 1 mm; a stopwatch: 0.01 s or 0.1 s). Choose an instrument with a small least count for the quantity you need.
Planning and doing a practicum
Plan like this: (1) write the aim and the formula, (2) list the direct readings, (3) choose instruments, (4) keep other things the same, (5) take readings in a table, (6) repeat at least 3 to 5 times, (7) calculate and add the error, (8) write the result with its error and a conclusion.
For the pendulum: use a thin thread, a small heavy bob, a small swing angle (under 10°), measure L from the pivot to the centre of the bob, time 10 to 20 swings, and start counting when the bob passes the middle.
Error bounds
No reading is exact. The absolute error Δx is the likely size of the doubt. It comes from the instrument (least count), from your reaction time, and from the spread of repeated readings (use half of max − min, or the standard deviation). The relative error is Δx/x and the percentage error is Δx/x × 100.
Combining: for sums and differences add the absolute errors. For products and quotients add the relative errors. A power counts as many times as the power: for g = 4π²L/T², Δg/g = ΔL/L + 2ΔT/T. The biggest term decides the quality, so improve that measurement first.
Graphs and hypothesis testing
A hypothesis is a clear guess that can fail. Here: T² ∝ L. Take readings at several L, plot T² (y) against L (x). If the points lie close to a straight line through the origin, the hypothesis is supported. The slope is 4π²/g, so g = 4π² ÷ slope.
To check an accepted value, compare the difference with the error bound. If |your value − accepted| is smaller than your error bound, the result agrees. If it is much larger, look for a mistake or a hidden effect (like a heavy thread or a big swing angle) before blaming the theory.
Reviewing the whole physics course
Review physics as a map, not a list. Mechanics (motion, force, energy), heat (molecules and temperature), electricity and magnetism (charges, fields, circuits, waves), waves and optics, atoms and quanta, and the Universe. Three threads join them: conservation laws (energy, momentum, charge), models and where they fail, and measurement with units and errors.
Good revision habit: for every chapter write the one main law, its units, one experiment, and one real-life use. Check that units match on both sides of each formula. Practise with mixed questions, not chapter by chapter.
Try it
Hang a small weight on a thread of length 1.00 m. Time 10 swings with a phone stopwatch, 5 times. Find the mean T and g. Change the length to 0.50 m and repeat. Does T² fall to half? In the 3D, press New trial set a few times and watch how the dots move but the mean stays close to 9.8.
Key formulas and definitions
- T = (time of n swings) ÷ n
- g = 4π²L / T²
- Relative error = Δx / x; percentage error = Δx/x × 100
- Product or quotient: Δz/z = Δa/a + Δb/b; power: Δz/z = n × Δa/a
- Graph of T² against L: slope = 4π² / g
- Agreement test: |measured − accepted| ≤ error bound
Worked examples
1. The mean time for 10 swings is 17.9 s and L = 0.800 m. Find T and g.
T = 17.9 ÷ 10 = 1.79 s. g = 4π²L/T² = 39.48 × 0.800 / 3.204 = 9.86 m/s².
2. Five values of T are 1.80, 1.78, 1.82, 1.79, 1.81 s. Find the mean and the error from the spread.
Mean = 9.00 ÷ 5 = 1.80 s. Spread: (1.82 − 1.78) ÷ 2 = 0.02 s. So T = 1.80 ± 0.02 s.
3. A cube has mass 54.0 ± 0.1 g and side 3.00 ± 0.01 cm. Find its density with error.
ρ = 54.0 / 27.0 = 2.00 g/cm³. Relative error = 0.1/54.0 + 3 × 0.01/3.00 = 0.19% + 1.0% = 1.2%. Δρ = 0.024, so ρ = 2.00 ± 0.02 g/cm³.
4. In the pendulum, L = 0.800 ± 0.002 m, T = 1.79 ± 0.02 s. Find the percentage error in g.
ΔL/L = 0.25%; ΔT/T = 1.1%, counted twice = 2.2%. Δg/g = 0.25 + 2.2 = 2.5%. With g = 9.86, Δg = 0.25.
5. V = 6.0 ± 0.1 V and I = 0.50 ± 0.01 A. Find R = V/I with its error.
R = 12 Ω. Relative error = 0.1/6.0 + 0.01/0.50 = 1.7% + 2.0% = 3.7%. ΔR = 0.44, so R = 12.0 ± 0.4 Ω.
6. The T²–L graph has slope 4.00 s²/m. Find g, and say if it agrees with 9.81 ± 0.2.
g = 4π²/slope = 39.48 / 4.00 = 9.87 m/s². The difference from 9.81 is 0.06, smaller than 0.2, so it agrees.
Common mistakes
- Measuring L only to the top of the bob instead of to its centre.
- Timing one swing only, so the reaction error is large. Time 10 or more.
- Adding percentage errors for sums. For sums add absolute errors.
- Forgetting that T² doubles the percentage error of T.
- Quoting 9.8567 m/s² when the error is ±0.25. Give 9.9 ± 0.3 or 9.86 ± 0.25.