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Mechanical Efficiency: How Much Work Is Really Useful?

No real machine turns all the work you put in into useful work. Some is wasted on friction and on moving the machine parts. Efficiency η = useful work ÷ total work × 100%. It is always less than 100%. Oiling and using lighter parts raise it.

🎬 Step-by-step story

  1. An ideal machine has no loss. Lifting 60 N by 1 m is 60 J of useful work, and you put in 30 N × 2 m = 60 J. Efficiency 100%.
  2. A real pulley weighs 10 N and has 5 N of friction. You must put in 40 N × 2 m = 80 J, but only 60 J is useful.
  3. Efficiency η = useful ÷ total × 100 = 60 ÷ 80 × 100 = 75%. The 20 J left is wasted: 10 J lifts the pulley and 10 J fights friction.
  4. Oil the rope. Friction drops from 5 N to 1 N. Total work 72 J, wasted 12 J, efficiency about 83%.
  5. Use a lighter pulley (2 N) and keep the oil. Total work 64 J, wasted only 4 J, efficiency about 94%. Never 100%.
  6. Your turn: change the load, the pulley weight and the friction. Watch the efficiency and the wasted work.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why does an ideal machine matter if it does not exist?

It is a reference. It shows the best possible case (100%) so we can see how much the real machine loses.

Where does the lost 20 J go?

It is not destroyed. It becomes heat and sound from friction, and it lifts the pulley itself.

Can efficiency be more than 100%?

No. That would mean getting more work out than you put in. The green bar can never be taller than the total bar.

How does oil help?

Oil makes surfaces slide easily, so the friction force is smaller and less work is wasted.

Is a lighter pulley always better?

Yes for efficiency: less weight to lift means less wasted work. It must still be strong enough to be safe.

Does a bigger load change the efficiency?

Yes. With the same pulley and friction, a bigger load makes the useful part larger, so η goes up. Try it in free play.

Useful work and total work

When you use a machine, you do work on it. This is the total work (work input) = effort × distance the effort moves.

The machine does work on the load. This is the useful work (work output) = load × distance the load moves.

Energy is never lost, it just goes to places where we do not want it. Wasted work = total work − useful work.

η: calculating efficiency

Efficiency (η, say "eta") = useful work ÷ total work × 100%.

It tells us what part of the work you put in becomes useful. It has no unit.

Steps

  1. Find useful work: load × height lifted.
  2. Find total work: effort × distance the effort moves.
  3. Divide useful by total, multiply by 100.

Example: useful work 60 J, total work 80 J. η = 60 ÷ 80 × 100 = 75%.

η is always less than 100% for a real machine. A value above 100% means a mistake.

Link to mechanical advantage

Efficiency = actual MA ÷ ideal MA × 100. A pulley block with 4 strands has ideal MA 4. If it really gives MA 3, then η = 3 ÷ 4 = 75%.

Improving efficiency

To waste less, cut the two big losses.

Remember: no machine has 100% efficiency. Even the best gear box loses some energy as heat.

Try it: raise the green, shrink the red

In the last 3D step, set load 60 N, pulley 10 N and friction 5 N (η = 75%). Now set friction to 0. What is η? (60 ÷ 70 = 86%.) Now set the pulley weight to 0 too. (100%.) Then double the load with pulley 10 N and friction 5 N: does η go up or down?

At home

Slide a book down a rough ramp and a smooth ramp. Which one wastes more energy as heat? Rub your palms for 10 seconds: that warm feeling is wasted work.

Key formulas and definitions

Worked examples

1. A machine does 80 J of total work and 60 J of it is useful. Find η and the wasted work.

η = 60 ÷ 80 × 100 = 75%. Wasted = 80 − 60 = 20 J.

2. A pulley system lifts a 50 N load by 2 m. The effort is 30 N and it moves 4 m. Find the efficiency.

Useful = 50 × 2 = 100 J. Total = 30 × 4 = 120 J. η = 100 ÷ 120 × 100 = 83.3%.

3. A crate of 500 N is raised 1 m by pushing it up a 5 m ramp with 150 N. Find the efficiency.

Useful = 500 × 1 = 500 J. Total = 150 × 5 = 750 J. η = 500 ÷ 750 × 100 = 66.7%. The rest is lost to friction.

4. A pump has 60% efficiency. It takes 800 J of energy. How much is useful and how much is wasted?

Useful = 60% of 800 = 480 J. Wasted = 800 − 480 = 320 J.

5. A pulley block has 4 strands. It lifts a 200 N load with a 70 N effort. Find the efficiency.

For 1 m lift: useful = 200 J. Rope pulled = 4 m, total = 70 × 4 = 280 J. η = 200 ÷ 280 × 100 = 71.4%. Or: actual MA = 200 ÷ 70 = 2.86, ideal MA = 4, η = 2.86 ÷ 4 = 71.4%.

6. A movable pulley (2 strands) weighs 10 N and has 5 N of friction. It lifts a 90 N load. Find the effort and the efficiency. Then find the efficiency for a 190 N load.

Effort = (90 + 10) ÷ 2 + 5 = 55 N. For a 1 m lift: useful = 90 J, total = 55 × 2 = 110 J. η = 90 ÷ 110 = 81.8%. For 190 N: effort = (190 + 10) ÷ 2 + 5 = 105 N, total = 210 J, η = 190 ÷ 210 = 90.5%. A bigger load makes the machine more efficient.

Common mistakes

Practice quiz

1. Efficiency of a machine is:
2. Useful work is 90 J and total work is 120 J. The efficiency is:
3. Which can never happen for a real machine?
4. Oiling a machine mainly:
5. Wasted work equals:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What is the formula for mechanical efficiency?

η = (useful work ÷ total work) × 100%, or (actual MA ÷ ideal MA) × 100%.

Why is efficiency always less than 100%?

Some work is always wasted against friction and in moving the machine parts, so the useful work is less than the work put in.

How can we improve the efficiency of a machine?

Reduce friction (oil, smooth surfaces, bearings), use lighter moving parts, and keep the machine in good order.

Where this is taught

China八年级(初二)Ch.12 Simple machines

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