Assumptions of kinetic theory
To build a simple model, we assume:
- A gas is made of a very large number of identical molecules.
- The molecules are tiny: their own size is negligible compared with the gaps between them.
- They move in all directions at random, with many speeds.
- They do not attract or repel each other, except during collisions.
- Collisions (with each other and with walls) are perfectly elastic: kinetic energy is not lost.
- A collision takes almost no time compared with the time between collisions.
- Newton's laws apply to each molecule. Gravity on them is ignored.
Pressure of an ideal gas: the derivation
Take a cube of side l with N molecules, each of mass m.
Step 1: one hit
A molecule with x-velocity vₓ hits the right wall and comes back with −vₓ. Its momentum change is −2mvₓ, so the wall receives 2mvₓ.
Step 2: how often
It goes across and back (2l) before hitting the same wall again. Time between hits = 2l/vₓ. Hits per second = vₓ/2l.
Step 3: force from one molecule
Force = momentum per second = 2mvₓ × vₓ/2l = mvₓ²/l.
Step 4: all molecules
F = (m/l) Σ vₓ². Pressure P = F/l² = (m/l³) Σ vₓ² = (m N/V) × average of vₓ².
Step 5: share out directions
Motion is random, so the average of vₓ² = average of v_y² = average of v_z² = ⅓ v̄² (mean square speed). So
P = ⅓ n m v̄² = ⅓ ρ v̄², where n = N/V and ρ = nm is the density.
So PV = ⅓ N m v̄² = ⅔ × (total translational kinetic energy).
Kinetic meaning of temperature
Compare PV = ⅓ N m v̄² with the gas equation PV = N kB T:
⅓ m v̄² = kB T, so average KE of one molecule = ½ m v̄² = (3/2) kB T.
- Temperature is a measure of the average kinetic energy of the molecules.
- It does not depend on the gas: at the same T, a hydrogen and an oxygen molecule have the same average KE.
- Total KE of one mole = (3/2) RT.
- At absolute zero, this model says the random motion would stop.
rms speed
The root mean square (rms) speed is found in three steps: square all speeds, take their mean, then take the square root.
vrms = √(v̄²) = √(3kBT/m) = √(3RT/M) = √(3P/ρ)
- vrms ∝ √T: four times the kelvin temperature gives twice the speed.
- vrms ∝ 1/√M: at the same T, lighter gases are faster.
- Oxygen at 300 K: vrms ≈ 483 m/s, faster than sound in air.
Other averages: mean speed v̄ = √(8RT/πM) and most probable speed vp = √(2RT/M). Order: vp < v̄ < vrms.
Try it: the 3D and at home
- In the 3D: pick O₂ at 300 K and note vrms. Predict the value at 1200 K (4 times T), then check. Switch to H₂ and predict again.
- At home: put one drop of ink in cold water and one in hot water. The hot one spreads faster, because its molecules move faster.
Board exam focus
- The 5-step pressure derivation is a frequent 5-mark question. Draw the cube and show 2mvₓ.
- Link: P = ⅔ E, where E is the translational KE per unit volume.
- Average KE = (3/2) kT does not depend on mass.
- Numericals: ratio of rms speeds = √(M₂/M₁) at the same T.
Key formulas and definitions
- Momentum to wall per hit = 2mvₓ
- P = ⅓ n m v̄² = ⅓ ρ v̄²
- PV = ⅓ N m v̄² = ⅔ E_total
- Average KE per molecule = ½ m v̄² = (3/2) k_B T
- KE of 1 mole = (3/2) RT
- v_rms = √(3k_BT/m) = √(3RT/M) = √(3P/ρ)
- v_rms1 / v_rms2 = √(M₂/M₁)
- v_p = √(2RT/M), v̄ = √(8RT/πM)
Worked examples
1. Four molecules have speeds 2, 4, 6 and 8 m/s. Find their rms speed.
Step 1: squares: 4, 16, 36, 64. Step 2: mean = 120/4 = 30. Step 3: square root. Answer: v_rms = √30 ≈ 5.48 m/s (the plain mean is 5 m/s).
2. Find the average kinetic energy of a gas molecule at 27 °C. (k = 1.38 × 10⁻²³ J/K)
Step 1: T = 300 K. Step 2: KE = (3/2) k T = 1.5 × 1.38 × 10⁻²³ × 300. Answer: KE ≈ 6.21 × 10⁻²¹ J.
3. Find the rms speed of oxygen molecules at 300 K. (M = 32 g/mol, R = 8.31)
Step 1: M = 0.032 kg/mol. Step 2: v_rms = √(3 × 8.31 × 300 / 0.032) = √(233719). Answer: v_rms ≈ 483 m/s.
4. At what temperature will the rms speed of a gas be double its value at 27 °C?
Step 1: v_rms ∝ √T. Step 2: to double v, T must become 4 times. Step 3: T = 4 × 300 = 1200 K. Answer: 1200 K = 927 °C.
5. Compare the rms speeds of hydrogen (M = 2) and oxygen (M = 32) at the same temperature.
Step 1: v_H/v_O = √(M_O/M_H). Step 2: = √(32/2) = √16. Answer: hydrogen is 4 times faster.
6. A gas has density 1.25 kg/m³ at a pressure of 1.0 × 10⁵ Pa. Find the rms speed of its molecules.
Step 1: v_rms = √(3P/ρ). Step 2: = √(3 × 10⁵ / 1.25) = √(240000). Answer: v_rms ≈ 490 m/s.
7. Find the total translational kinetic energy of 2 mol of helium at 400 K. (R = 8.31)
Step 1: KE for n moles = (3/2) n R T. Step 2: = 1.5 × 2 × 8.31 × 400. Answer: KE ≈ 9.97 × 10³ J.
Common mistakes
- Taking the rms speed as the plain average speed. Square first, then average, then take the root.
- Thinking heavier molecules have more KE at the same temperature. Average KE = (3/2)kT, the same for all gases.
- Using M in g/mol in √(3RT/M). M must be in kg/mol.
- Forgetting that the wall receives 2mvₓ per hit, not mvₓ, because the velocity reverses.