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Polar Coordinates

Polar coordinates give the position of a point by its distance r from a fixed point (the pole) and the angle θ turned anticlockwise from a fixed ray (the initial line). Convert with x = r cosθ, y = r sinθ, and back with r² = x² + y², tanθ = y/x (check the quadrant). Equations r = f(θ) draw circles, cardioids, limaçons, roses and spirals. Calculus: slope dy/dx = (dy/dθ)/(dx/dθ), area = ½∫r²dθ.

🎬 Step-by-step story

  1. This is a polar grid. The black dot is the pole O. Circles show distance from O. The dark ray going right is the initial line, where θ = 0.
  2. A red point appears. Its distance from the pole is r = 3. The red arm shows r. Distance alone is not enough: many points are 3 away.
  3. The purple arc grows from the initial line. It turns anticlockwise to θ = 40°. Now the point is fixed: (r, θ) = (3, 40°).
  4. Blue and green legs drop from the point. Blue is x = r cosθ ≈ 2.3. Green is y = r sinθ ≈ 1.9. Same point, now in (x, y).
  5. An orange curve is drawn as θ goes round. At each angle its distance is r = 2(1 + cosθ). The heart shape is a cardioid.
  6. Your turn: move r and θ, and pick curves. Try the rose r = 4cos2θ and count its petals.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Where is θ = 0?

Along the initial line, the dark ray to the right of the pole.

Why is r alone not enough?

All points on a circle are the same distance from O. You also need the direction.

Can one point have two polar names?

Yes. Adding 360° to θ, or using −r with θ + 180°, lands on the same point.

Why does tan⁻¹(y/x) sometimes give the wrong angle?

tan repeats every 180°, so (1, 1) and (−1, −1) give the same tan. Look at the signs of x and y to choose the quadrant.

Why does the cardioid touch the pole?

At θ = 180°, r = 2(1 + cos180°) = 0, so the curve passes through O.

Why does r = 4cos2θ have 4 petals, not 2?

With n even, negative r values draw new petals on the opposite side, so you get 2n = 4.

What are polar coordinates?

Pick a fixed point O called the pole and a fixed ray from it called the initial line (like the positive x-axis). A point P is given by (r, θ): r = distance OP, θ = angle from the initial line to OP, measured anticlockwise.

The same point has many names: (3, 40°) = (3, 400°) = (−3, 220°). A negative r means "go the opposite way". Many courses use the principal form r ≥ 0, −π < θ ≤ π.

Converting between polar and Cartesian

Polar → Cartesian: x = r cosθ, y = r sinθ.

Cartesian → polar: r = √(x² + y²), tanθ = y/x. Always check the quadrant: for (−1, −1), tanθ = 1 but θ = 225° (or −135°), not 45°.

Equations convert too: x² + y² = 9 becomes r = 3; y = x becomes θ = 45°; x = 2 becomes r = 2 secθ.

Polar curves

To sketch: make a table of θ (0°, 30°, 60° …) and r, look for symmetry (cosθ only → symmetric about the initial line), and note where r = 0 (the curve passes through the pole).

Calculus with polar curves

With x = r cosθ and y = r sinθ where r = f(θ):

Try it

Draw a polar grid on paper with a compass and protractor. Plot r = 2(1 + cosθ) for θ = 0°, 60°, 90°, 120°, 180° and join the dots. Check your heart shape against the 3D scene.

Key formulas and definitions

Worked examples

1. Convert (4, 60°) to Cartesian.

x = 4cos60° = 2, y = 4sin60° = 2√3 ≈ 3.46. Point (2, 3.46).

2. Convert (−3, 3) to polar with r > 0.

r = √(9 + 9) = 3√2 ≈ 4.24. tanθ = −1 and the point is in quadrant II, so θ = 135°. Answer (3√2, 135°).

3. Write x² + y² = 6x in polar form.

r² = 6r cosθ → r = 6cosθ. A circle through O with centre (3, 0).

4. How many petals does r = 3sin4θ have? r = 5cos3θ?

n = 4 is even → 8 petals. n = 3 is odd → 3 petals.

5. Find the area inside r = 2 for θ from 0 to π/2.

A = ½∫₀^{π/2} 4 dθ = 2 × π/2 = π. (A quarter of a circle of radius 2: ¼ × 4π = π. ✓)

6. Find the area enclosed by the cardioid r = 1 + cosθ.

A = ½∫₀^{2π}(1 + cosθ)² dθ = ½∫(1 + 2cosθ + cos²θ)dθ = ½(2π + 0 + π) = 3π/2.

7. For r = 2θ, is the point moving away from the pole at θ = 1? Find dy/dx there.

dr/dθ = 2 > 0, so it moves away. dy/dx = (2sin1 + 2cos1)/(2cos1 − 2sin1) = (0.841 + 0.540)/(0.540 − 0.841) ≈ −4.59.

Common mistakes

Practice quiz

1. In (r, θ), r is:
2. (2, 90°) in Cartesian is:
3. x² + y² = 25 in polar is:
4. r = 2(1 + cosθ) is a:
5. Area in polar form is:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

What are polar coordinates used for?

For anything circular or rotating: radar, orbits, antennas, sound patterns of microphones, and curves like spirals.

How do I convert polar to Cartesian?

Use x = r cosθ and y = r sinθ.

Can r be negative?

Yes. A negative r means you go the opposite way from the direction θ points.

Where this is taught

England (GCSE, A level)Year 12G Polar coordinates (part 1)
England (GCSE, A level)Year 13G Polar coordinates (part 2)
USA (Common Core, NGSS, AP)Grade 12Trigonometric and Polar Functions
USA (Common Core, NGSS, AP)Grade 12Polar and parametric
Japan高校3年Curves and the complex plane

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