Quadrilaterals inscribed in a circle
A cyclic quadrilateral is a four-sided shape whose four corners all lie on one circle. We say the quadrilateral is inscribed in the circle. Four points on a circle are called concyclic.
Main rule: opposite angles add up to 180°. So ∠A + ∠C = 180° and ∠B + ∠D = 180°.
Outside angle rule: if you extend one side, the angle outside at that corner equals the inside angle at the opposite corner.
Converse: if a quadrilateral has one pair of opposite angles adding to 180°, then it is cyclic.
Why opposite angles add up to 180°
Take the centre O. The angle at the centre on arc BCD is twice ∠A (angle at the edge). The angle at the centre on the other arc BAD is twice ∠C. The two centre angles together make one full turn, 360°. So 2∠A + 2∠C = 360°. Divide by 2: ∠A + ∠C = 180°.
Which quadrilaterals can be cyclic? Squares, rectangles and isosceles trapeziums always can. A parallelogram is cyclic only if it is a rectangle, because its opposite angles are equal and must also add to 180°, so each is 90°. A rhombus that is not a square is never cyclic.
Quadrilaterals around a circle (tangential)
A tangential quadrilateral has a circle inside it that touches all four sides. Every side is a tangent. From one corner, the two tangents to the circle are equal in length. Adding these equal pairs round the shape gives:
AB + CD = BC + DA (sums of opposite sides are equal). This is the Pitot theorem.
The converse is also true: if the sums of opposite sides are equal, a circle fits inside. Squares, rhombuses and kites have an incircle. For any shape with an incircle, Area = r × s where r is the inradius and s is half the perimeter.
A shape can be both: a square is cyclic and tangential.
Converse of the intercept (Thales) theorem
The intercept theorem says: a line parallel to one side of a triangle cuts the other two sides in the same ratio. The converse says: if a line cuts two sides of a triangle in the same ratio, the line is parallel to the third side.
In triangle ABC, let D be on AB and E on AC. If AD/DB = AE/EC, then DE ∥ BC. This is a quick way to prove two lines are parallel, and it often helps to show that a quadrilateral is a trapezium before checking whether it is cyclic.
Typical exam questions
- Find a missing angle using ∠A + ∠C = 180°.
- Prove that four points are concyclic (use the converse).
- Use the outside angle rule in a diagram with an extended side.
- Find a missing side of a tangential quadrilateral.
- Prove that a cyclic parallelogram is a rectangle.
Try it at home
Draw a circle with a bowl or a coin. Mark four points on it and join them. Measure opposite angles with a protractor and add them. Do you get 180°, give or take a degree or two? Now cut a kite shape from paper and try to fit a coin inside, touching all four sides. Then check the side sums.
Key formulas and definitions
- Cyclic: ∠A + ∠C = 180°, ∠B + ∠D = 180°
- Outside angle = opposite inside angle
- Tangential: AB + CD = BC + DA
- Area of a tangential quadrilateral = r × s (s = half the perimeter)
- Converse of Thales: AD/DB = AE/EC ⟹ DE ∥ BC
Worked examples
1. ABCD is cyclic and ∠A = 75°. Find ∠C.
Opposite angles add to 180°. ∠C = 180° − 75° = 105°.
2. ABCD is cyclic and ∠B = 110°. Find ∠D.
∠D = 180° − 110° = 70°.
3. In a cyclic quadrilateral the side AB is extended to P. The outside angle at B is 85°. Find the inside angle at D.
The outside angle at B equals the opposite inside angle ∠D. So ∠D = 85°. (Check: ∠B = 180° − 85° = 95°, and 95° + 85° = 180°.)
4. The angles A, B, C of a cyclic quadrilateral are in the ratio 2 : 3 : 4. Find all four angles.
∠A + ∠C = 180°, so 2x + 4x = 180°, x = 30°. ∠A = 60°, ∠B = 90°, ∠C = 120°. ∠D = 180° − 90° = 90°.
5. A quadrilateral has sides AB = 7, BC = 6, CD = 9. A circle touches all four sides. Find DA.
AB + CD = 7 + 9 = 16. This equals BC + DA = 6 + DA. So DA = 10.
6. A tangential quadrilateral has perimeter 36 cm and inradius 4 cm. Find its area.
s = 36 ÷ 2 = 18 cm. Area = r × s = 4 × 18 = 72 cm².
7. Prove: a parallelogram inscribed in a circle is a rectangle.
In a parallelogram opposite angles are equal: ∠A = ∠C. In a cyclic quadrilateral ∠A + ∠C = 180°. So 2∠A = 180°, ∠A = 90°. A parallelogram with one right angle is a rectangle.
8. In triangle ABC, D is on AB with AD = 3, DB = 6, and E is on AC with AE = 2, EC = 4. Is DE parallel to BC?
AD/DB = 3/6 = 1/2 and AE/EC = 2/4 = 1/2. The ratios are equal, so by the converse of the intercept theorem, DE ∥ BC.
Common mistakes
- Adding adjacent angles (A + B) instead of opposite angles (A + C).
- Using the 180° rule for a quadrilateral whose corners are not all on one circle.
- Mixing up the two rules: angles belong to the cyclic case, sides belong to the tangential case.
- Calling every parallelogram cyclic. Only the rectangle is.