Stereoisomerism and chiral centres
Stereoisomers have the same structural formula but a different arrangement of atoms in space. Two kinds are studied: E/Z (geometric) isomerism around C=C, and optical isomerism.
A chiral centre (asymmetric carbon) is a carbon atom bonded to four different atoms or groups. It is often shown with an asterisk, C*. A molecule with one chiral centre always has two optical isomers.
How to find one: look at each sp³ carbon. Ignore any carbon with two H atoms (CH₂, CH₃) or a double bond. For the rest, check that all four groups are different, looking along the whole chain, not just the first atom. Example: in butan-2-ol, CH₃CH(OH)CH₂CH₃, carbon 2 holds H, OH, CH₃ and C₂H₅: chiral.
Enantiomers and plane-polarised light
The two optical isomers are enantiomers: non-superimposable mirror images. To draw them, draw the carbon with two bonds in the plane, one wedge (towards you) and one dash (away), then draw its reflection in a mirror line.
Ordinary light vibrates in all planes. A polarising filter lets through light vibrating in one plane only: plane-polarised light. When it passes through a solution of one enantiomer, the plane is turned:
- one enantiomer turns it clockwise: (+) or dextrorotatory
- the other turns it by the same angle anticlockwise: (−) or laevorotatory
A substance that rotates the plane is optically active. Enantiomers have the same melting point, boiling point and reactions with non-chiral reagents. They can react differently with other chiral molecules, such as enzymes and receptors in the body.
Racemic mixtures
A racemic mixture (racemate) contains equal amounts of both enantiomers. Their rotations cancel, so it is optically inactive.
Racemic mixtures often form in reactions that create a chiral centre from a planar group:
- Nucleophilic addition to C=O: e.g. HCN/CN⁻ adding to ethanal. The C=O is flat, so the nucleophile can attack from above or below with equal chance, giving a 50 : 50 mix of the two enantiomers of 2-hydroxypropanenitrile.
- SN1 reactions through a flat carbocation, and electrophilic addition to an unsymmetrical alkene that makes a new chiral centre.
Drug makers may need to separate the enantiomers or use chiral catalysts to make just one, because the two may have different effects in the body.
Try it: the hand and mirror test
Make a model with a ball (or a potato) and four toothpicks with four different coloured sweets. Make a second model as its mirror image in a real mirror. Try to turn one so that all four colours match the other. You cannot. Now make two sweets the same colour: suddenly the models match. In the 3D, free play lets you do the same thing.
Key formulas and definitions
- Chiral centre: C bonded to 4 different atoms/groups (C*)
- n chiral centres → at most 2ⁿ stereoisomers
- (+) clockwise, (−) anticlockwise, same angle for a pair of enantiomers
- Racemic mixture = 50 : 50 → net rotation 0° → optically inactive
- Planar intermediate (C=O, carbocation) + attack from both sides → racemic product
Worked examples
1. Does propan-2-ol, CH₃CH(OH)CH₃, have a chiral centre?
Step 1: Carbon 2 holds H, OH, CH₃ and CH₃. Step 2: Two groups are the same (CH₃). Answer: no chiral centre, no optical isomers.
2. Identify the chiral centre in 2-hydroxypropanoic acid (lactic acid), CH₃CH(OH)COOH.
Step 1: Carbon 1 (COOH) has a C=O: not chiral. Carbon 3 (CH₃) has three H: not chiral. Step 2: Carbon 2 holds H, OH, CH₃, COOH: four different groups. Answer: carbon 2 is the chiral centre.
3. Which of these is chiral: 1-chlorobutane or 2-chlorobutane?
Step 1: 1-chlorobutane: C1 has two H; other carbons are CH₂/CH₃. No chiral centre. Step 2: 2-chlorobutane: C2 holds H, Cl, CH₃, C₂H₅. Answer: 2-chlorobutane is chiral.
4. One enantiomer of a compound rotates plane-polarised light by +14°. What does the other enantiomer do, and the racemic mixture?
Step 1: Enantiomers rotate by the same amount in opposite directions: −14°. Step 2: A 50 : 50 mix: +14° and −14° cancel. Answer: −14°; racemic mixture 0°.
5. Explain why HCN addition to propanal gives an optically inactive product even though the product has a chiral centre.
Step 1: The C=O carbon and its groups lie in a flat plane. Step 2: CN⁻ can attack from above or below with equal chance. Step 3: Each side gives a different enantiomer, so 50 : 50 forms. Answer: a racemic mixture forms; rotations cancel.
6. How many stereoisomers at most can a molecule with 2 chiral centres have?
Step 1: Each chiral centre can be in 2 arrangements. Step 2: 2 × 2 = 2² = 4. Answer: up to 4 (fewer if the molecule has internal symmetry).
Common mistakes
- Counting a CH₂ or CH₃ carbon as chiral. It has at least two identical H atoms.
- Looking only at the first atom of each group. CH₂CH₃ and CH₃ are different groups even though both start with C.
- Saying enantiomers have different boiling points. They are the same; only the direction of rotation (and action with chiral things) differs.
- Saying a racemic mixture is not chiral. Each molecule is chiral; the mixture is just optically inactive.