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Power Distribution and Electrical Work in Ships and Factories

Distribution carries electricity from the source (generator or grid) to many loads. A main switchboard receives the three-phase supply and sends it through feeders, each with a breaker or fuse. Transformers give the right voltage (for example 440 V down to 230 V). Ships and factories use the same ideas: separate circuits for power and lighting, protection against overload and short circuit, and an earth wire. Electrical work means installing, testing and repairing this system safely.

🎬 Step-by-step story

  1. The source: a generator feeds the main switchboard. From the board, cables called feeders will carry power to every load.
  2. Three-phase: the board has three live wires, red, yellow and blue. Their waves are one third of a cycle apart, so some wire is always giving strong power.
  3. Transformer: motors may run on 440 V, but lights need 230 V. A transformer steps the voltage down for the lighting feeder.
  4. Loads: each load has its own feeder. The motor takes 12 A. When the lights join, 5 A is added. Total current is the sum.
  5. Protection: the heater joins and the total reaches 27 A. The breaker is rated 25 A, so it trips and opens by itself. This stops the cables from overheating.
  6. Free play: switch loads, reset the breaker, and test a fault in the motor casing with and without the earth wire.

Tip: drag the 3D scene to turn it. Use two fingers to zoom.

🤔 Common doubts, cleared

Why does a ship need its own generators?

A ship at sea has no connection to a city grid. Its diesel generators make electricity, and having more than one means the ship can keep power if one stops.

Why three wires and not one?

With three phases, when one wave is low another is high, so power is smooth and motors turn smoothly. The same copper also carries more power.

Why do we need a transformer for the lights?

Lights and sockets are made for about 230 V, but big motors use 440 V. A transformer gives the right voltage to each.

Why does the total current go up when I switch on more loads?

Each load is joined in parallel and takes its own current. The feeder carries all of them together, so the currents add.

Why must the breaker be smaller than what the cable can carry?

The breaker protects the cable. If the current is more than the cable can carry the cable heats up, so the breaker must trip first. Here it trips above 25 A.

Why is the casing dangerous without an earth wire?

A fault wire touching the metal makes the casing live, but no big current flows, so the breaker does not trip. A person touching it becomes the path to earth.

What is power distribution?

Power distribution means carrying electricity from where it is made or received to where it is used. The main parts are:

Most plants use three-phase power for large loads. A three-phase supply has three live wires (R, Y, B) whose voltages peak at different times, one third of a cycle apart. Motors run smoothly on it, and the same cable size carries more power. Single-phase 230 V is taken between one phase and the neutral for lights and small devices. In a 400 V (line-to-line) system, each phase to neutral is 400 / √3 ≈ 230 V.

Shipboard power distribution

A ship is a floating island, so it makes its own electricity. Typical layout:

  1. Two or three diesel generators make three-phase AC (commonly 440 V, 60 Hz on many ships; other ships use 400 V, 50 Hz). More than one runs, so a failure does not stop the ship.
  2. The main switchboard in the engine control room joins them together (this is called paralleling) and sends power to feeders.
  3. A step-down transformer gives 230 V or 115 V for lighting, sockets and navigation equipment through an emergency or lighting switchboard.
  4. The emergency switchboard has its own small generator and batteries, so the steering gear and emergency lights work if the main supply fails.
  5. When the ship is in port, shore supply can replace the generators through a shore connection box.

Special care on ships: salty damp air attacks metal and insulation, so cables are armoured and sealed, and the system is checked often for insulation resistance. Most ship systems are insulated neutral, so a single earth fault gives an alarm instead of a trip, and the crew can repair it before a second fault occurs.

Factory power distribution

A factory takes high-voltage supply (for example 11 kV) and steps it down with a transformer substation to about 400 V three-phase. Then:

Selective protection: the breaker nearest the fault should trip first, so only the faulty part loses power. Breakers closer to the source have bigger ratings and trip later.

Power for a three-phase load: P = √3 × V × I × cos φ (V = line voltage, I = line current, cos φ = power factor).

Electrical work: installing, testing and staying safe

Electrical work includes laying cables, fixing switches and boards, joining wires, fitting equipment and testing. Good practice:

Try it: the load budget

Write the current of every appliance in your room (power in watts ÷ 230 V). For example a 2000 W heater takes 8.7 A and a 60 W fan takes 0.26 A. Add them up and compare with the room breaker (often 16 A). In the 3D, switch on the motor and lights, then add the heater and watch the total pass 25 A and the breaker trip. Next, switch on the earth fault with the earth wire removed and read what happens to the casing.

Key formulas and definitions

Worked examples

1. Find the line-to-neutral voltage of a 400 V three-phase supply.

V_phase = 400 / √3 = 400 / 1.732 ≈ 231 V, about 230 V.

2. A three-phase motor takes 10 A from a 400 V supply at power factor 0.8. Find its power input.

P = √3 × V × I × cos φ = 1.732 × 400 × 10 × 0.8 = 5542 W ≈ 5.5 kW.

3. A feeder has a motor (12 A), lights (5 A) and a heater (10 A). The breaker is rated 25 A. What happens when all are on?

Total = 12 + 5 + 10 = 27 A. This is above 25 A, so the breaker trips.

4. A 2 kW heater runs from 230 V. Find the current and pick a standard fuse (6 A, 10 A, 16 A).

I = 2000 / 230 ≈ 8.7 A. The next standard value above this is a 10 A fuse.

5. A cable of resistance 0.05 Ω carries 20 A. Find the voltage drop and the power lost.

Drop = I R = 20 × 0.05 = 1 V. Power lost = I² R = 400 × 0.05 = 20 W.

6. Voltage at the source is 230 V and the cable drops 1 V. What percent of the supply is lost?

1 / 230 × 100 ≈ 0.43 %. This is small and acceptable.

7. A factory machine uses 3 kW for 8 hours a day. The cost is ₹8 per unit. What is the cost for 26 working days?

Energy = 3 × 8 × 26 = 624 kWh. Cost = 624 × 8 = ₹4992.

Common mistakes

Practice quiz

1. What is the main job of a feeder?
2. In a three-phase supply the phases are apart by:
3. What does the earth wire do in a fault?
4. A step-down transformer on a ship is used to:
5. Before working on a circuit you should:

Practice: answer these yourself

Type or choose your answer, then press Check. Use a hint if you are stuck; the full solution appears after you answer.

Frequently asked questions

Why do ships and factories use three-phase power?

Three-phase gives smoother power, makes motors self-starting and uses less copper for the same power than single-phase.

What is the difference between a fuse and a circuit breaker?

Both cut the circuit when the current is too high. A fuse has a thin wire that melts and must be replaced. A breaker opens a switch and can be reset.

Why must metal casings be earthed?

If a live wire touches the casing, the earth wire carries a big current that trips the breaker. Without earth, the casing stays live and can shock a person.

Where this is taught

Japan高校(専門学科)1〜3年Electrical Theory

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