Step 1 and 2: list and measure
An energy audit means finding out where energy goes. Write down each appliance, its power in watts (W) (it is printed on the label) and the hours it runs each day.
Energy = power × time. If power is in kilowatts and time in hours, energy is in kilowatt-hours (kWh). One kWh is one "unit" on the bill. 1 kW = 1000 W.
Example: a 1500 W cooler for 4 hours uses 1.5 × 4 = 6 kWh.
Step 3: find the biggest user
Add up all the kWh. The appliance with the tallest bar is where a small change gives the biggest saving. Heaters, coolers, geysers and air conditioners usually use the most, because their power is large. A fridge has small power but runs all day, so it also adds up.
Step 4 and 5: cut by habit and by device
Habit changes cost nothing: switch off lights and fans in empty rooms, use natural light, run a washing machine with a full load, unplug chargers (standby power wastes energy).
Device changes cost money now and save later: LED bulbs (9 W give about the same light as a 60 W old bulb), star-rated appliances, better insulation, solar water heater.
An efficient device turns more of its input energy into useful output. Efficiency = useful energy out ÷ energy in × 100%.
Check the plan: cost and payback
New total kWh tells how much you saved. Cost saved = kWh saved × price per unit. For a device change, payback time = cost of the new device ÷ money saved per day. A good plan has a short payback time. Write the plan as a table: appliance, old kWh, change, new kWh, saving. Then check it again after a month with your meter reading.
Key formulas and definitions
- E (kWh) = P (kW) × t (h)
- 1 kW = 1000 W; 1 kWh = 3.6 × 10^6 J
- Cost = kWh × price per unit
- Efficiency = useful output / input × 100%
- Payback time = cost of device / saving per day
Worked examples
1. A 60 W bulb glows for 5 hours. How many kWh does it use?
P = 0.06 kW. E = 0.06 × 5 = 0.3 kWh.
2. An LED of 9 W replaces the 60 W bulb (5 hours a day). How much energy is saved per day?
Old: 0.3 kWh. New: 0.009 × 5 = 0.045 kWh. Saving = 0.255 kWh per day.
3. A home uses 12 kWh per day. The price is 8 per unit. What is the bill for 30 days?
Energy = 12 × 30 = 360 kWh. Bill = 360 × 8 = 2880.
4. An LED costs 120 and saves 2 per day. What is its payback time?
Payback = 120 / 2 = 60 days.
Common mistakes
- Using watts and hours directly to get kWh. Change W to kW first (divide by 1000).
- Saving on the small items first. Start with the biggest user.
- Forgetting standby power. A charger or TV in standby still uses a little all day.
- Thinking a cheap bulb is always cheaper. Count the electricity it uses over its life.